Question
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In order to start a small business, a student takes out a simple interest loan for \( \$ 6000 \) for 3 months at a rate of \( 7.25 \% \). a. How much interest must the student pay? b. Find the future value of the loan. a. The amount of interest is \( \$ \square \). (Round to the nearest cent as needed.)

Ask by Mills Brooks. in the United States
Jan 23,2025

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Answer

a. The amount of interest is \$108.75. b. The future value of the loan is \$6,108.75.

Solution

Let's calculate both parts step by step. ### a. **Amount of Interest** To find the simple interest, we'll use the formula: \[ I = P \times r \times t \] Where: - \( P \) = Principal amount (\$6,000) - \( r \) = Annual interest rate (7.25% or 0.0725) - \( t \) = Time in years (3 months = 0.25 years) Plugging in the values: \[ I = 6000 \times 0.0725 \times 0.25 \] \[ I = 6000 \times 0.018125 \] \[ I = 108.75 \] **a. The amount of interest is \$108.75.** ### b. **Future Value of the Loan** The future value (FV) of the loan is the sum of the principal and the interest: \[ FV = P + I \] \[ FV = 6000 + 108.75 \] \[ FV = 6108.75 \] **b. The future value of the loan is \$6,108.75.**

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To calculate the interest, we can use the formula for simple interest: \[ I = P \times r \times t \] where: - \( I \) is the interest, - \( P \) is the principal amount (loan amount), - \( r \) is the interest rate (as a decimal), and - \( t \) is the time in years. Given: - \( P = 6000 \), - \( r = 7.25\% = \frac{7.25}{100} = 0.0725 \), - \( t = 3 \text{ months} = \frac{3}{12} = 0.25 \text{ years} \). Plugging in the values: \[ I = 6000 \times 0.0725 \times 0.25 \] \[ I = 6000 \times 0.0725 \times 0.25 = 108.75 \] So, the amount of interest is \( \$ 108.75 \). To find the future value of the loan, we can use: \[ FV = P + I \] Calculating the future value: \[ FV = 6000 + 108.75 = 6108.75 \] Thus, the future value of the loan is \( \$ 6108.75 \). The amount of interest is \( \$ 108.75 \).

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