\( 1 \leftarrow \quad \begin{array}{l}\text { Solve for } x . \text { Check your solution. } \\ 2 x+6 x=24\end{array} \quad \begin{array}{l}x=\square \text { (Simplify your answer.) }\end{array} \)

To solve for \( x \) in the equation \( 2x + 6x = 24 \), first, combine the like terms on the left side. This gives you \( 8x = 24 \). Now, divide both sides by 8 to isolate \( x \): \( x = \frac{24}{8} = 3 \). To check your solution, plug \( x = 3 \) back into the original equation: \( 2(3) + 6(3) = 6 + 18 = 24 \), which confirms that the solution is correct! So, \( x = 3 \).