Multiply the special product. $$ (\sqrt{3}+y)(\sqrt{3}-y)=\square $$

Question

UpStudy AI · Accepted Answer

To multiply the given expression $$(\sqrt{3} + y)(\sqrt{3} - y)$$, you can use the **difference of squares** formula:

$$
(a + b)(a - b) = a^2 - b^2
$$

Here, $$a = \sqrt{3}$$ and $$b = y$$. Applying the formula:

$$
(\sqrt{3} + y)(\sqrt{3} - y) = (\sqrt{3})^2 - y^2 = 3 - y^2
$$

**Final Answer:**
$$
3 - y^{2}
$$
$$ 3 - y^{2} $$

Multiply the special product. \[ (\sqrt{3}+y)(\sqrt{3}-y)=\square \]