24. Six pencils cost \( \$ 174 \). Three of the same pencils and an eraser cost \( \$ 122 \). What is the cost of the eraser? A. \( \$ 25 \) B. \( \$ 33 \) C. \( \$ 35 \) D. \( \$ 59 \)
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To solve for the cost of the eraser, we first need to determine the cost of one pencil. If six pencils cost \( \$ 174 \), then the cost of one pencil can be calculated as follows: \[ \text{Cost of one pencil} = \frac{174}{6} = 29 \] Next, we can plug this value into the second part of the problem where three pencils and an eraser cost \( \$ 122 \): \[ 3 \times 29 + \text{Cost of eraser} = 122 \] Calculating the cost of three pencils: \[ 87 + \text{Cost of eraser} = 122 \] Now, isolating the cost of the eraser: \[ \text{Cost of eraser} = 122 - 87 = 35 \] Therefore, the cost of the eraser is \( \$ 35 \). So, the correct answer is C. \( \$ 35 \).