Solve using elimination. \( \begin{array}{l}8 x+9 y=17 \\ -3 x-2 y=-5\end{array} \)
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To use the elimination method, we want to eliminate one of the variables by making the coefficients of that variable the same in both equations. Let's focus on eliminating \( y \). First, we can manipulate the coefficients of \( y \) in both equations. Multiply the first equation by 2 and the second equation by 9: 1) \( 2(8x + 9y) = 2(17) \) → \( 16x + 18y = 34 \) 2) \( 9(-3x - 2y) = 9(-5) \) → \( -27x - 18y = -45 \) Now we can add these two equations together: \[ (16x + 18y) + (-27x - 18y) = 34 - 45 \] This simplifies to: \[ -11x = -11 \] Dividing both sides by -11 gives us: \[ x = 1 \] Now that we have \( x \), we can substitute it back into one of the original equations to find \( y \). Let's use the first equation: \[ 8(1) + 9y = 17 \] This simplifies to: \[ 8 + 9y = 17 \] Subtract 8 from both sides: \[ 9y = 9 \] Dividing both sides by 9 gives us: \[ y = 1 \] Thus, the solution to the system of equations is: \[ (x, y) = (1, 1) \]