Ind the polar form of $$ 8 i $$. Simplify any radicals. Express the argument $$ heta $$ in degrees, with $$ 0^{\circ} \leq heta

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Ind the polar form of $$ 8 i $$. Simplify any radicals. Express the argument $$ 	heta $$ in degrees, with $$ 0^{\circ} \leq 	heta<360^{\circ} $$. \begin{tabular}{|l|l|l|}\hline$$ i $$ & ( \ \hline & $$ \sin $$ & $$ \cos $$ \ \hline\end{tabular}

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1. Write the number in the form $$ a + bi $$. For $$ 8i $$, the real part is $$ a = 0 $$ and the imaginary part is $$ b = 8 $$.

2. Compute the magnitude $$ r $$ using  
   $$
   r = \sqrt{a^2 + b^2}.
   $$
   Substituting the values,
   $$
   r = \sqrt{0^2 + 8^2} = \sqrt{64} = 8.
   $$

3. Find the argument $$ \theta $$. Since $$ a = 0 $$ and $$ b > 0 $$, the complex number is located on the positive imaginary axis. Therefore,
   $$
   \theta = 90^\circ.
   $$

4. Write the polar form of the complex number as  
   $$
   r(\cos \theta + i\sin \theta).
   $$
   Substituting $$ r = 8 $$ and $$ \theta = 90^\circ $$,
   $$
   8i = 8\left(\cos 90^\circ + i\sin 90^\circ\right).
   $$

Thus, the polar form of $$ 8i $$ is  
$$
8\left(\cos 90^\circ + i\sin 90^\circ\right).
$$
The polar form of $$ 8i $$ is $$ 8(\cos 90^\circ + i\sin 90^\circ) $$.

Ind the polar form of .
Simplify any radicals. Express the argument in degrees, with .

(

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