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Give the center and radius of the circle described by the equation and graph the equation. Use the graph to identify the relation's domain and range. \( (x-2)^{2}+(y-5)^{2}=16 \)

Ask by Long Dickson. in the United States
Feb 04,2025

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The circle has a center at (2, 5) and a radius of 4. Its domain is from -2 to 6 on the x-axis and its range is from 1 to 9 on the y-axis.

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Bonus Knowledge

The equation of the circle is given by \((x-2)^{2}+(y-5)^{2}=16\). This is in the standard form \((x-h)^{2}+(y-k)^{2}=r^{2}\), where \((h,k)\) is the center and \(r\) is the radius. Here, the center of the circle is \((2, 5)\) and the radius is \(r = \sqrt{16} = 4\). To graph the circle, plot the center at \((2, 5)\) and then use the radius to mark points that are 4 units away in all directions (up, down, left, right) from the center. The domain of the circle, reflecting the x-values, ranges from \([-2, 6]\) and the range, reflecting the y-values, spans from \([1, 9]\). Enjoy drawing your circle! It’s the perfect round shape to capture the essence of geometry!

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