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Find the greatest common factor of these three expressions, \[ 5 y^{4}, 21 y^{3} \text {, and } 15 y^{5} \] \[ \text { [7] } \]

Ask by Ayala Little. in the United States
Feb 03,2025

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Answer

The greatest common factor is \( y^{3} \).

Solution

To find the greatest common factor (GCF) of the three expressions \(5y^{4}\), \(21y^{3}\), and \(15y^{5}\), we'll analyze both the numerical coefficients and the variable parts separately. **1. Numerical Coefficients:** - **Factors of 5:** 1, 5 - **Factors of 21:** 1, 3, 7, 21 - **Factors of 15:** 1, 3, 5, 15 The **common factor** among 5, 21, and 15 is **1**. **2. Variable Parts:** - \(y^{4}\) - \(y^{3}\) - \(y^{5}\) For the variable \(y\), the GCF is the lowest power of \(y\) present in all terms, which is \(y^{3}\). **Combining both parts**, the GCF of the three expressions is: \[ 1 \times y^{3} = y^{3} \] **Answer:** \( y^{3} \)

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To find the greatest common factor (GCF) of the expressions \(5 y^{4}\), \(21 y^{3}\), and \(15 y^{5}\), we can break down each coefficient and factor in variable terms. The coefficients are 5, 21, and 15. The prime factorization of each coefficient is: - \(5 = 5^1\) - \(21 = 3^1 \times 7^1\) - \(15 = 3^1 \times 5^1\) The common factors among these coefficients are the prime factors, and the only one present in all three is not existent. Therefore, there are no common factors from coefficients, which means the GCF of the coefficients is 1. Next, we look at the variable part. The lowest power of \(y\) common to all expressions is \(y^3\). Combining the results, the GCF of the three expressions is: \[ GCF = 1 \cdot y^{3} = y^{3} \] Thus, the greatest common factor of \(5 y^{4}\), \(21 y^{3}\), and \(15 y^{5}\) is \(y^{3}\).

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