Use synthetic division to find the result when \( x^{3}-9 x^{2}+4 x+4 \) is divided by \( x-1 \). If there is a remainder, express the result in the form \( q(x)+\frac{r(x)}{b(x)} \)
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To perform synthetic division of \( x^{3}-9 x^{2}+4 x+4 \) by \( x-1 \), we use the root of \( x-1 \) which is \( 1 \). 1. Write down the coefficients of the polynomial: \( 1, -9, 4, 4 \). 2. Set up synthetic division: ``` 1 | 1 -9 4 4 | 1 -8 -4 ---------------------- 1 -8 -4 0 ``` 3. Bring down the first coefficient (1). 4. Multiply it by \( 1 \) and write it under the second coefficient (-9): \( -9 + 1 = -8 \). 5. Multiply \( -8 \) by \( 1 \) and add to the next coefficient: \( 4 - 8 = -4 \). 6. Multiply \( -4 \) by \( 1 \) and add to \( 4 \): \( 4 - 4 = 0 \) (remainder). The final row shows \( 1, -8, -4 \), meaning the result of the division is \( x^2 - 8x - 4 \) with a remainder of \( 0 \). Thus, we can express this as: \[ q(x) = x^2 - 8x - 4 \quad \text{and} \quad r(x) = 0. \] Therefore, the answer is: \[ x^{3} - 9x^{2} + 4x + 4 = (x^2 - 8x - 4) \cdot (x - 1) + 0. \]