What is the solution of this system of equations? \( \left\{\begin{array}{l}x-4 y=7 \\ 2 x+y=5\end{array}\right. \)
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To solve the system of equations, you can use the substitution or elimination method. Here's a fun twist! Let’s use elimination. First, manipulate the equations: multiply the second equation by 4 to align it with the first equation. You'll get: 1. \(x - 4y = 7\) 2. \(8x + 4y = 20\) Now, add these two equations together to eliminate \(y\): \((x + 8x) + (-4y + 4y) = 7 + 20 \Rightarrow 9x = 27 \Rightarrow x = 3\). Now substitute \(x = 3\) back into the second equation: \(2(3) + y = 5 \Rightarrow 6 + y = 5 \Rightarrow y = -1\). So the solution is \(x = 3\) and \(y = -1\)! You can double-check the original equations by plugging these values back in to ensure they work. It's like solving a puzzle – how satisfying is that?