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What is the solution of this system of equations? \( \left\{\begin{array}{l}x-4 y=7 \\ 2 x+y=5\end{array}\right. \)

Ask by Cole Watkins. in the United States
Feb 04,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The solution is \( x = 3 \) and \( y = -1 \).

Solution

To solve the system of equations: \[ \begin{cases} x - 4y = 7 \\ 2x + y = 5 \end{cases} \] **Step 1: Solve the first equation for \( x \).** \[ x - 4y = 7 \\ \Rightarrow x = 7 + 4y \] **Step 2: Substitute \( x = 7 + 4y \) into the second equation.** \[ 2x + y = 5 \\ 2(7 + 4y) + y = 5 \\ 14 + 8y + y = 5 \\ 14 + 9y = 5 \] **Step 3: Solve for \( y \).** \[ 9y = 5 - 14 \\ 9y = -9 \\ y = -1 \] **Step 4: Substitute \( y = -1 \) back into the expression for \( x \).** \[ x = 7 + 4(-1) \\ x = 7 - 4 \\ x = 3 \] **Solution:** \[ x = 3 \\ y = -1 \] **Verification:** Plugging \( x = 3 \) and \( y = -1 \) into both original equations: 1. \( 3 - 4(-1) = 3 + 4 = 7 \) ✔️ 2. \( 2(3) + (-1) = 6 - 1 = 5 \) ✔️ Both equations are satisfied, confirming the solution is correct. **Final Answer:** The solution is \( x = 3 \) and \( y = -1 \).

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To solve the system of equations, you can use the substitution or elimination method. Here's a fun twist! Let’s use elimination. First, manipulate the equations: multiply the second equation by 4 to align it with the first equation. You'll get: 1. \(x - 4y = 7\) 2. \(8x + 4y = 20\) Now, add these two equations together to eliminate \(y\): \((x + 8x) + (-4y + 4y) = 7 + 20 \Rightarrow 9x = 27 \Rightarrow x = 3\). Now substitute \(x = 3\) back into the second equation: \(2(3) + y = 5 \Rightarrow 6 + y = 5 \Rightarrow y = -1\). So the solution is \(x = 3\) and \(y = -1\)! You can double-check the original equations by plugging these values back in to ensure they work. It's like solving a puzzle – how satisfying is that?

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