Question
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Question 5
Set it up as \( x+5>12 \) or \( x+5<-12 \) and then solve for \( x \) by subtracting 5
from both sides of each inequality.
Mrompts each equation or inequality with the correct descri
solve for \( x \) by subtracting 5 from both sides of the inequality:
(1) \( x+5<12 \)
Set it up as \( -12
Ask by Gibbs Franklin. in the United States
Jan 24,2025
Ask by Gibbs Franklin. in the United States
Jan 24,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
Solutions:
1. \( x < 7 \)
2. \( -17 < x < 7 \)
3. \( x = 7 \) or \( x = -17 \)
4. \( -17 < x < 7 \)
Solution
Let's solve each part of the problem step by step.
### (1) Solve the inequality \( x + 5 < 12 \)
1. **Set up the inequality**:
\[
x + 5 < 12
\]
2. **Subtract 5 from both sides**:
\[
x < 12 - 5
\]
\[
x < 7
\]
### (2) Set up the compound inequality \( -12 < x + 5 < 12 \)
1. **Set up the compound inequality**:
\[
-12 < x + 5 < 12
\]
2. **Subtract 5 from all three sides**:
\[
-12 - 5 < x + 5 - 5 < 12 - 5
\]
\[
-17 < x < 7
\]
### (3) Solve the equation \( |x + 5| = 12 \)
1. **Set up the two equations**:
\[
x + 5 = 12 \quad \text{or} \quad x + 5 = -12
\]
2. **Solve each equation by subtracting 5**:
- For \( x + 5 = 12 \):
\[
x = 12 - 5
\]
\[
x = 7
\]
- For \( x + 5 = -12 \):
\[
x = -12 - 5
\]
\[
x = -17
\]
### (4) Solve the inequality \( |x + 5| < 12 \)
1. **Set up the compound inequality**:
\[
-12 < x + 5 < 12
\]
2. **Subtract 5 from all three sides**:
\[
-12 - 5 < x + 5 - 5 < 12 - 5
\]
\[
-17 < x < 7
\]
### Summary of Results
1. For \( x + 5 < 12 \): \( x < 7 \)
2. For \( -12 < x + 5 < 12 \): \( -17 < x < 7 \)
3. For \( |x + 5| = 12 \): \( x = 7 \) or \( x = -17 \)
4. For \( |x + 5| < 12 \): \( -17 < x < 7 \)
These results provide the solutions for each part of the problem.
Reviewed and approved by the UpStudy tutoring team
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Extra Insights
Alright, let's dive into the world of inequalities and absolute value! For the first inequality \( x+5>12 \), when you subtract 5 from both sides, you get \( x>7 \). Similarly, for \( x+5<-12 \), subtracting 5 gives \( x<-17 \). This tells us that \( x \) can be greater than 7 or less than -17—simple, right?
Next up, let's tackle \( |x+5|=12 \). You break this into two equations: \( x+5=12 \) leads to \( x=7 \) and \( x+5=-12 \) gives \( x=-17 \). For \( |x+5|<12 \), you’d write it as \( -12