When a dynamic array with a class for a base type is declared, which constructor is called? the copy constructor the default constructor the destructor an explicit constructor

When you declare a dynamic array of objects in C++, such as: ```cpp Base* array = new Base[n]; ``` Here’s what happens: 1. **Memory Allocation:** Memory is allocated for `n` objects of type `Base`. 2. **Constructor Calls:** For each of the `n` objects, the **default constructor** of the `Base` class is called to initialize the objects. The default constructor is the constructor that can be called with no arguments. **Explanation of Other Options:** - **Copy Constructor:** This is used when a new object is created as a copy of an existing object, not when initializing an array of new objects. - **Destructor:** This is called when objects are destroyed, typically using `delete[] array;`, not during the array's creation. - **Explicit Constructor:** This keyword is used to prevent implicit conversions and isn't directly related to initializing arrays unless specific constructor overloading is involved. **Conclusion:** When you declare a dynamic array of a class type without providing specific initialization parameters, the **default constructor** is invoked for each element in the array. **Answer:** The default constructor