Question 6(Multiple Choice Worth 1 points) \( \begin{array}{l}(05.02 \text { MC) } \\ \text { Solve the following system of equations: } \\ -2 x+3 y=7 \\ y=3 x+7\end{array} \)

Solve the system of equations \( -2x+3y=7;y=3x+7 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}-2x+3y=7\\y=3x+7\end{array}\right.\) - step1: Substitute the value of \(y:\) \(-2x+3\left(3x+7\right)=7\) - step2: Simplify: \(7x+21=7\) - step3: Move the constant to the right side: \(7x=7-21\) - step4: Subtract the numbers: \(7x=-14\) - step5: Divide both sides: \(\frac{7x}{7}=\frac{-14}{7}\) - step6: Divide the numbers: \(x=-2\) - step7: Substitute the value of \(x:\) \(y=3\left(-2\right)+7\) - step8: Simplify: \(y=1\) - step9: Calculate: \(\left\{ \begin{array}{l}x=-2\\y=1\end{array}\right.\) - step10: Check the solution: \(\left\{ \begin{array}{l}x=-2\\y=1\end{array}\right.\) - step11: Rewrite: \(\left(x,y\right) = \left(-2,1\right)\) The solution to the system of equations is \( x = -2 \) and \( y = 1 \).