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factorise \( 3 x^{4}-3 x^{2}-27 x^{2}+27 \)

Ask by Murray Owen. in South Africa
Feb 03,2025

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Answer

The polynomial \( 3x^{4} - 3x^{2} - 27x^{2} + 27 \) factors to \( 3(x - 3)(x + 3)(x - 1)(x + 1) \).

Solution

To factorize the polynomial \( 3x^{4} - 3x^{2} - 27x^{2} + 27 \), follow these steps: 1. **Combine Like Terms:** \[ 3x^{4} - 3x^{2} - 27x^{2} + 27 = 3x^{4} - 30x^{2} + 27 \] 2. **Factor Out the Greatest Common Factor (GCF):** \[ 3x^{4} - 30x^{2} + 27 = 3(x^{4} - 10x^{2} + 9) \] 3. **Factor the Quartic Polynomial:** Let \( y = x^{2} \). Then the expression becomes: \[ y^{2} - 10y + 9 \] This quadratic factors as: \[ y^{2} - 10y + 9 = (y - 1)(y - 9) \] Substitute back \( y = x^{2} \): \[ (x^{2} - 1)(x^{2} - 9) \] 4. **Factor Further Using the Difference of Squares:** \[ x^{2} - 1 = (x - 1)(x + 1) \\ x^{2} - 9 = (x - 3)(x + 3) \] 5. **Combine All Factors:** \[ 3(x - 1)(x + 1)(x - 3)(x + 3) \] **Final Factored Form:** \[ 3(x - 3)(x + 3)(x - 1)(x + 1) \] Answer: After factoring, the polynomial is 3 (x – 3)(x + 3)(x – 1)(x + 1)

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Mind Expander

To factorise the expression \( 3x^{4} - 3x^{2} - 27x^{2} + 27 \), let's first combine like terms. The expression simplifies to: \( 3x^{4} - 30x^{2} + 27 \). Next, we can factor out a common factor of 3: \( 3(x^{4} - 10x^{2} + 9) \). Now, let’s set \( y = x^{2} \), which transforms the quadratic into: \( 3(y^{2} - 10y + 9) \). Now we can factor the quadratic: \( y^{2} - 10y + 9 = (y - 1)(y - 9) \). Substituting back for \( y \): \( 3((x^{2} - 1)(x^{2} - 9)) \). Recognising the difference of squares, \( x^{2} - 1 = (x - 1)(x + 1) \) and \( x^{2} - 9 = (x - 3)(x + 3) \): So, the final factorised form is: \( 3(x - 1)(x + 1)(x - 3)(x + 3) \).

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