Solve the inequality \( 1+\frac{x-5}{3}-2 x<-4 \)
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To solve the inequality \( 1+\frac{x-5}{3}-2 x<-4 \), we start by simplifying the expression. First, isolate the fraction: \[ \frac{x-5}{3} - 2x + 1 < -4 \] Next, subtract 1 from both sides: \[ \frac{x-5}{3} - 2x < -5 \] Now, multiply the whole inequality by 3 to eliminate the fraction (remembering that multiplying by a positive number does not change the direction of the inequality): \[ x - 5 - 6x < -15 \] Combine like terms: \[ -5x - 5 < -15 \] Add 5 to both sides: \[ -5x < -10 \] Now, divide by -5 and remember to flip the inequality symbol: \[ x > 2 \] Thus, the solution to the inequality is: \[ \boxed{x > 2} \]