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Use your calculator to check your 1. Write each of these tatios in its simplest form. c) \( 7: 21: 35 \) a) \( 15 ; 20 \) b) \( 200: 180 \) f) 9 min 000 s d) \( 102: 99: 87 \) e) \( 75 \mathrm{~m}: 125 \mathrm{~cm} \) Write each of these as a rate. Use the units given In brackets. a) Mpho buys four dozen eggs for R48. (R/dozen) b) Dan can eat three bananas in 90 seconds. (bananas/min) c) A cartravels 616 km on 56 litres of petrol. ( \( \mathrm{km} / \mathrm{\ell} \) ) d) A snail crawls 150 cm in 2 hours. ( \( \mathrm{cm} / \mathrm{min} \) ) Which is faster: \( 1 \mathrm{~m} / \mathrm{s} \) or \( 1 \mathrm{~km} / \mathrm{h} \) ? Pat is knitting a scarf. On average she can knit 2 cm in 35 minutes. a) Express this as a rate in \( \mathrm{min} / \mathrm{cm} \). b) Express this as a rate in \( \mathrm{mm} / \mathrm{min} \). c) How long will it take her to knit a scarf that is 160 cm long?

Ask by Kirk Conner. in South Africa
Feb 04,2025

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Tutor-Verified Answer

Answer

**Simplified Answers:** 1. **Simplifying Ratios:** - **a)** \(15 : 20 = 3 : 4\) - **b)** \(200 : 180 = 10 : 9\) - **c)** \(7 : 21 : 35 = 1 : 3 : 5\) - **d)** \(102 : 99 : 87 = 34 : 33 : 29\) - **e)** \(75\, \text{m} : 125\, \text{cm} = 60 : 1\) - **f)** \(9\, \text{min} : 000\, \text{s}\) is undefined. 2. **Writing as Rates:** - **a)** R12/dozen - **b)** 2 bananas/min - **c)** 11 km/ℓ - **d)** 1.25 cm/min 3. **Comparing Speeds:** - \(1\, \text{m/s}\) is faster than \(1\, \text{km/h}\). 4. **Pat’s Knitting Rate:** - **a)** 17.5 min/cm - **b)** ≈0.571 mm/min - **c)** 2800 minutes (or 46 hours and 40 minutes) If you need more detailed explanations or further assistance, feel free to ask!

Solution

Sure, let's work through each of your questions step by step. --- ### **1. Simplifying Ratios** **a) \(15 : 20\)** - **Find the Greatest Common Divisor (GCD):** The GCD of 15 and 20 is 5. - **Simplify:** \[ \frac{15}{5} : \frac{20}{5} = 3 : 4 \] - **Simplest Form:** \(3 : 4\) --- **b) \(200 : 180\)** - **Find the GCD:** The GCD of 200 and 180 is 20. - **Simplify:** \[ \frac{200}{20} : \frac{180}{20} = 10 : 9 \] - **Simplest Form:** \(10 : 9\) --- **c) \(7 : 21 : 35\)** - **Find the GCD:** The GCD of 7, 21, and 35 is 7. - **Simplify:** \[ \frac{7}{7} : \frac{21}{7} : \frac{35}{7} = 1 : 3 : 5 \] - **Simplest Form:** \(1 : 3 : 5\) --- **d) \(102 : 99 : 87\)** - **Find the GCD:** The GCD of 102, 99, and 87 is 3. - **Simplify:** \[ \frac{102}{3} : \frac{99}{3} : \frac{87}{3} = 34 : 33 : 29 \] - **Simplest Form:** \(34 : 33 : 29\) --- **e) \(75\, \text{m} : 125\, \text{cm}\)** - **Convert Units:** \[ 75\, \text{m} = 7500\, \text{cm} \] - **Form the Ratio:** \(7500 : 125\) - **Find the GCD:** The GCD of 7500 and 125 is 25. - **Simplify:** \[ \frac{7500}{25} : \frac{125}{25} = 300 : 5 \] - **Further Simplify:** \[ \frac{300}{5} : \frac{5}{5} = 60 : 1 \] - **Simplest Form:** \(60 : 1\) --- **f) \(9\, \text{min} : 000\, \text{s}\)** - It seems there's a typo here. If it's intended to be \(9\, \text{min} : 0\, \text{s}\), the ratio is undefined because division by zero is not possible. --- ### **2. Writing as Rates** **a) Mpho buys four dozen eggs for R48. (R/dozen)** - **Calculate Rate:** \[ \text{Rate} = \frac{48\, \text{R}}{4\, \text{dozen}} = 12\, \text{R/dozen} \] - **Rate:** **R12/dozen** --- **b) Dan can eat three bananas in 90 seconds. (bananas/min)** - **Convert Seconds to Minutes:** \[ 90\, \text{seconds} = 1.5\, \text{minutes} \] - **Calculate Rate:** \[ \frac{3\, \text{bananas}}{1.5\, \text{minutes}} = 2\, \text{bananas/min} \] - **Rate:** **2 bananas/min** --- **c) A car travels 616 km on 56 litres of petrol. (\( \mathrm{km} / \mathrm{\ell} \))** - **Calculate Rate:** \[ \frac{616\, \text{km}}{56\, \text{ℓ}} = 11\, \text{km/ℓ} \] - **Rate:** **11 km/ℓ** --- **d) A snail crawls 150 cm in 2 hours. (\( \mathrm{cm} / \mathrm{min} \))** - **Convert Hours to Minutes:** \[ 2\, \text{hours} = 120\, \text{minutes} \] - **Calculate Rate:** \[ \frac{150\, \text{cm}}{120\, \text{minutes}} = 1.25\, \text{cm/min} \] - **Rate:** **1.25 cm/min** --- ### **3. Comparing Speeds** **Which is faster: \(1\, \text{m/s}\) or \(1\, \text{km/h}\)?** - **Convert \(1\, \text{km/h}\) to m/s:** \[ 1\, \text{km/h} = \frac{1000\, \text{m}}{3600\, \text{s}} \approx 0.2778\, \text{m/s} \] - **Comparison:** \[ 1\, \text{m/s} > 0.2778\, \text{m/s} \] - **Conclusion:** **\(1\, \text{m/s}\) is faster.** --- ### **4. Pat’s Knitting Rate** **Pat can knit 2 cm in 35 minutes.** **a) Express this as a rate in \(\mathrm{min/cm}\).** - **Calculate Rate:** \[ \frac{35\, \text{min}}{2\, \text{cm}} = 17.5\, \text{min/cm} \] - **Rate:** **17.5 min/cm** --- **b) Express this as a rate in \(\mathrm{mm/min}\).** - **Convert cm to mm:** \[ 2\, \text{cm} = 20\, \text{mm} \] - **Calculate Rate:** \[ \frac{20\, \text{mm}}{35\, \text{min}} \approx 0.571\, \text{mm/min} \] - **Rate:** **≈0.571 mm/min** --- **c) How long will it take her to knit a scarf that is 160 cm long?** - **Using the Rate \(17.5\, \text{min/cm}\):** \[ 160\, \text{cm} \times 17.5\, \text{min/cm} = 2800\, \text{minutes} \] - **Convert to Hours and Minutes (optional):** \[ 2800\, \text{minutes} = 46\, \text{hours} \, 40\, \text{minutes} \] - **Time Required:** **2800 minutes** (or **46 hours and 40 minutes**) --- If you have any further questions or need more detailed explanations on any of these steps, feel free to ask!

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To simplify the ratios: a) The simplest form of \( 15:20 \) is \( 3:4 \) (both divided by 5). b) The simplest form of \( 200:180 \) is \( 10:9 \) (both divided by 20). c) The simplest form of \( 7:21:35 \) is \( 1:3:5 \) (all divided by 7). d) The simplest form of \( 102:99:87 \) is \( 34:33:29 \) (all divided by 3). e) The simplest form of \( 75 \mathrm{~m}: 125 \mathrm{~cm} \) is \( 6:5 \) (75 m is 7500 cm, so \( 7500:125 \) and then simplified). f) The time \( 9 \text{ min } 0 \text{ s} \) can be expressed as \( 9 \text{ min } \) or 540 seconds, simplifying rates when needed. Now, for the rates: a) Mpho buys eggs for \( \frac{R48}{4 \text{ dozen}} = R12 \text{/dozen} \). b) Dan's rate is \( \frac{3 \text{ bananas}}{90 \text{ seconds}} = 2 \text{ bananas/min} \). c) The car's mileage is \( \frac{616 \text{ km}}{56 \text{ litres}} = 11 \text{ km/l} \). d) The snail’s speed is \( \frac{150 \text{ cm}}{120 \text{ min}} = 1.25 \text{ cm/min} \). To determine which speed is faster, converting \( 1 \text{ km/h} \) to meters per second yields approximately \( 0.28 \text{ m/s} \), so \( 1 \text{ m/s} \) is indeed faster! For Pat's knitting: a) The rate is \( \frac{35 \text{ min}}{2 \text{ cm}} = 17.5 \text{ min/cm} \). b) To express in mm/min, \( 2 \text{ cm} = 20 \text{ mm} \) yields \( \frac{35 \text{ min}}{20 \text{ mm}} = 1.75 \text{ min/mm} \). c) To find out how long it will take for 160 cm, we use the rate: \( 160 \text{ cm} \times 17.5 \text{ min/cm} = 2800 \text{ min} = 46.67 \text{ hours} \).

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