Use your calculator to check your 1. Write each of these tatios in its simplest form. c) \( 7: 21: 35 \) a) \( 15 ; 20 \) b) \( 200: 180 \) f) 9 min 000 s d) \( 102: 99: 87 \) e) \( 75 \mathrm{~m}: 125 \mathrm{~cm} \) Write each of these as a rate. Use the units given In brackets. a) Mpho buys four dozen eggs for R48. (R/dozen) b) Dan can eat three bananas in 90 seconds. (bananas/min) c) A cartravels 616 km on 56 litres of petrol. ( \( \mathrm{km} / \mathrm{\ell} \) ) d) A snail crawls 150 cm in 2 hours. ( \( \mathrm{cm} / \mathrm{min} \) ) Which is faster: \( 1 \mathrm{~m} / \mathrm{s} \) or \( 1 \mathrm{~km} / \mathrm{h} \) ? Pat is knitting a scarf. On average she can knit 2 cm in 35 minutes. a) Express this as a rate in \( \mathrm{min} / \mathrm{cm} \). b) Express this as a rate in \( \mathrm{mm} / \mathrm{min} \). c) How long will it take her to knit a scarf that is 160 cm long?
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To simplify the ratios: a) The simplest form of \( 15:20 \) is \( 3:4 \) (both divided by 5). b) The simplest form of \( 200:180 \) is \( 10:9 \) (both divided by 20). c) The simplest form of \( 7:21:35 \) is \( 1:3:5 \) (all divided by 7). d) The simplest form of \( 102:99:87 \) is \( 34:33:29 \) (all divided by 3). e) The simplest form of \( 75 \mathrm{~m}: 125 \mathrm{~cm} \) is \( 6:5 \) (75 m is 7500 cm, so \( 7500:125 \) and then simplified). f) The time \( 9 \text{ min } 0 \text{ s} \) can be expressed as \( 9 \text{ min } \) or 540 seconds, simplifying rates when needed. Now, for the rates: a) Mpho buys eggs for \( \frac{R48}{4 \text{ dozen}} = R12 \text{/dozen} \). b) Dan's rate is \( \frac{3 \text{ bananas}}{90 \text{ seconds}} = 2 \text{ bananas/min} \). c) The car's mileage is \( \frac{616 \text{ km}}{56 \text{ litres}} = 11 \text{ km/l} \). d) The snail’s speed is \( \frac{150 \text{ cm}}{120 \text{ min}} = 1.25 \text{ cm/min} \). To determine which speed is faster, converting \( 1 \text{ km/h} \) to meters per second yields approximately \( 0.28 \text{ m/s} \), so \( 1 \text{ m/s} \) is indeed faster! For Pat's knitting: a) The rate is \( \frac{35 \text{ min}}{2 \text{ cm}} = 17.5 \text{ min/cm} \). b) To express in mm/min, \( 2 \text{ cm} = 20 \text{ mm} \) yields \( \frac{35 \text{ min}}{20 \text{ mm}} = 1.75 \text{ min/mm} \). c) To find out how long it will take for 160 cm, we use the rate: \( 160 \text{ cm} \times 17.5 \text{ min/cm} = 2800 \text{ min} = 46.67 \text{ hours} \).