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lence plot the graph of \( y=2(x+4)(x+2) \) on the same set of axes.

Ask by Hodgson Bob. in the United States
Jan 21,2025

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Answer

To plot the graph of \( y = 2(x + 4)(x + 2) \): 1. **Identify the roots:** \( x = -4 \) and \( x = -2 \). 2. **Find the vertex:** \( (-3, -2) \). 3. **Determine the y-intercept:** \( (0, 16) \). 4. **Plot the points and sketch the parabola** opening upwards with symmetry at \( x = -3 \). The graph will have its lowest point at \( (-3, -2) \), cross the x-axis at \( (-4, 0) \) and \( (-2, 0) \), and the y-axis at \( (0, 16) \).

Solution

Certainly! Let's analyze and plot the graph of the quadratic function: \[ y = 2(x + 4)(x + 2) \] ### Step 1: Expand the Equation First, expand the equation to standard form for easier analysis. \[ \begin{align*} y &= 2(x + 4)(x + 2) \\ &= 2(x^2 + 6x + 8) \\ &= 2x^2 + 12x + 16 \end{align*} \] ### Step 2: Identify Key Features 1. **Leading Coefficient (a):** \( a = 2 \) - Since \( a > 0 \), the parabola opens **upwards**. 2. **Roots (x-intercepts):** Set \( y = 0 \): \[ 2(x + 4)(x + 2) = 0 \implies x = -4 \text{ and } x = -2 \] - **Roots:** \( (-4, 0) \) and \( (-2, 0) \) 3. **Axis of Symmetry:** The axis of symmetry is the average of the roots: \[ x = \frac{-4 + (-2)}{2} = -3 \] 4. **Vertex:** Plug \( x = -3 \) into the equation to find \( y \): \[ y = 2(-3 + 4)(-3 + 2) = 2(1)(-1) = -2 \] - **Vertex:** \( (-3, -2) \) 5. **Y-intercept:** Set \( x = 0 \): \[ y = 2(0 + 4)(0 + 2) = 2(4)(2) = 16 \] - **Y-intercept:** \( (0, 16) \) ### Step 3: Plotting the Graph Here's a rough sketch of the graph with the identified key points: ``` y ^ | 16| * (0,16) | | | 8| | | | * (-4,0) * (-2,0) | | * 4| | | | 0|-------------------------> x | | | -2| * (-3,-2) | | ``` ### Step 4: Graph Description - **Vertex:** The lowest point of the parabola is at \( (-3, -2) \). - **Opening:** Since the leading coefficient is positive, the parabola opens upwards. - **Intercepts:** - **X-intercepts:** The graph crosses the x-axis at \( x = -4 \) and \( x = -2 \). - **Y-intercept:** The graph crosses the y-axis at \( y = 16 \). - **Symmetry:** The graph is symmetric about the line \( x = -3 \). ### Step 5: Additional Points (Optional) To make the graph more accurate, you can plot additional points. For example: - **When \( x = -5 \):** \[ y = 2(-5 + 4)(-5 + 2) = 2(-1)(-3) = 6 \quad \Rightarrow (-5, 6) \] - **When \( x = -1 \):** \[ y = 2(-1 + 4)(-1 + 2) = 2(3)(1) = 6 \quad \Rightarrow (-1, 6) \] Adding these points helps in sketching a more precise parabola. ### Final Sketch Combining all the information, the parabola will have its vertex at \( (-3, -2) \), intersect the x-axis at \( (-4, 0) \) and \( (-2, 0) \), and the y-axis at \( (0, 16) \). It will be symmetric about the line \( x = -3 \) and open upwards. --- If you have access to graphing tools or software (like Desmos, GeoGebra, or even graphing calculators), you can input the equation \( y = 2(x + 4)(x + 2) \) to visualize the graph more accurately.

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Extra Insights

To graph the function \( y=2(x+4)(x+2) \), start by determining the x-intercepts. Set \( y=0 \), which gives you the points \( x + 4 = 0 \) or \( x + 2 = 0 \), leading to \( x = -4 \) and \( x = -2 \). Next, identify the vertex of the parabola. Since it's a quadratic function, the vertex will be halfway between the x-intercepts, which is at \( x = -3 \). You can find the y-coordinate by plugging it back into the function. After plotting the x-intercepts and the vertex, draw a smooth curve through these points to form the parabola. Additionally, since the coefficient of \( 2 \) in front of the parenthesis makes the parabola open upwards and stretch vertically, you can choose additional points (like \( x = -5, -3, -1 \)) to enhance the accuracy of your graph. Once points are plotted, connect them to visualize the parabolic shape accurately!

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