(6) It snowed $$ 5 \frac{1}{2} $$ inches in January and $$ 4 \frac{7}{8} $$ inches in February. How many more inches did it snow in January than in February? Show your work.

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To determine how many more inches it snowed in **January** than in **February**, we'll subtract the snowfall in February from the snowfall in January. Here's a step-by-step breakdown of the calculation:

### Given:
- **January snowfall:** $$ 5 \frac{1}{2} $$ inches
- **February snowfall:** $$ 4 \frac{7}{8} $$ inches

### Step 1: Convert Mixed Numbers to Improper Fractions
First, convert both mixed numbers to improper fractions to make subtraction easier.

1. **January: $$ 5 \frac{1}{2} $$**
   $$
   5 \frac{1}{2} = \left(5 \times 2\right) + 1 = 10 + 1 = \frac{11}{2}
   $$

2. **February: $$ 4 \frac{7}{8} $$**
   $$
   4 \frac{7}{8} = \left(4 \times 8\right) + 7 = 32 + 7 = \frac{39}{8}
   $$

### Step 2: Find a Common Denominator
To subtract the two fractions, they must have the same denominator. The least common denominator (LCD) of 2 and 8 is **8**.

1. **Convert $$ \frac{11}{2} $$ to a fraction with denominator 8:**
   $$
   \frac{11}{2} = \frac{11 \times 4}{2 \times 4} = \frac{44}{8}
   $$

2. **$$ \frac{39}{8} $$ already has the denominator 8.**

### Step 3: Subtract the Fractions
Now, subtract the February snowfall from the January snowfall:

$$
\frac{44}{8} - \frac{39}{8} = \frac{44 - 39}{8} = \frac{5}{8}
$$

### Step 4: Interpret the Result
$$
\frac{5}{8} \text{ inches}
$$

### **Conclusion:**
It snowed **$$ \frac{5}{8} $$ inches** more in January than in February.
It snowed $$ \frac{5}{8} $$ inches more in January than in February.

(6) It snowed \( 5 \frac{1}{2} \) inches in January and \( 4 \frac{7}{8} \) inches in February. How many more inches did it snow in January than in February? Show your work.

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