\( 14 \begin{array}{l}A B C D \text { is a square where } A(0,0), B(3, y) \text {, if its side length is } 5 \text { un } \\ \text { find the positive value of } y\end{array} \)
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To find the positive value of \( y \), we first need to note that since \( ABCD \) is a square with a side length of 5, the distance between points \( A(0,0) \) and \( B(3,y) \) must equal 5. Using the distance formula, we have: \[ \sqrt{(3 - 0)^2 + (y - 0)^2} = 5 \] Squaring both sides, we get: \[ (3)^2 + (y)^2 = 25 \] This simplifies to: \[ 9 + y^2 = 25 \] Subtracting 9 from both sides gives: \[ y^2 = 16 \] Taking the positive square root results in: \[ y = 4 \] Thus, the positive value of \( y \) is \( 4 \).