Lesson \( 10-7 \) Exit Ticket Name ElkKilkal \( \begin{array}{ll}\text { 1. What is the product? } \\ 5 \frac{1}{4} \times 2 \frac{1}{3}=\text { ? } \\ \text { A. } 10 \frac{1}{12} & \text { B. } 12 \frac{3}{12} \\ \text { C. } 7 \frac{7}{12} & \text { D. } 12 \frac{1}{12} \\ \text { 2. What is the area of the rectangle? }\end{array} \)

To find the product of \( 5 \frac{1}{4} \times 2 \frac{1}{3} \), first convert the mixed numbers into improper fractions. So, \( 5 \frac{1}{4} = \frac{21}{4} \) and \( 2 \frac{1}{3} = \frac{7}{3} \). Multiply these together: \[ \frac{21}{4} \times \frac{7}{3} = \frac{147}{12} \] Now, convert \( \frac{147}{12} \) back into a mixed number: \[ 147 ÷ 12 = 12 \text{ remainder } 3 \] So, \( \frac{147}{12} = 12 \frac{3}{12} \) or simplified to \( 12 \frac{1}{4} \). Therefore, the closest answer isn't among your choices, unless \( D \) represents that equivalent value. Next, let’s talk about finding the area of a rectangle, which is done by multiplying the length by the width. If you're given specific dimensions (for example, length = 6 units and width = 4 units), you would calculate the area as \( 6 \times 4 = 24 \) square units. If you have different dimensions or need to find the area from a set problem, just remember: Always check your units and if they match up before you multiply!