Login
Premium
Home Question Bank Math Algebra
Question
upstudy study bank question image url

Put the following equation of a line into slope-intercept form, simplifying all fractions. \[ 10 x+8 y=72 \]

Ask by Davison Frazier. in the United States
Jan 27,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\( y = -\frac{5}{4}x + 9 \)

Solution

To convert the equation \(10x + 8y = 72\) into slope-intercept form (\(y = mx + b\)), follow these steps: 1. **Isolate the \(y\)-term:** \[ 8y = -10x + 72 \] 2. **Solve for \(y\) by dividing every term by 8:** \[ y = \frac{-10}{8}x + \frac{72}{8} \] 3. **Simplify the fractions:** \[ y = -\frac{5}{4}x + 9 \] **Final Answer:** \[ y = -\frac{5}{4}x + 9 \]

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Mind Expander

To convert the equation \( 10x + 8y = 72 \) into slope-intercept form (which is \( y = mx + b \)), we need to isolate \( y \). First, subtract \( 10x \) from both sides: \[ 8y = -10x + 72 \] Next, divide every term by \( 8 \) to solve for \( y \): \[ y = -\frac{10}{8}x + \frac{72}{8} \] Now simplify the fractions: \[ y = -\frac{5}{4}x + 9 \] So, the slope-intercept form is: \[ y = -\frac{5}{4}x + 9 \]

Related Questions

A. \( 3 x^{2}-x-10 \)
Algebra United Arab Emirates Jan 30, 2025
lify: \( \left(\frac{1447^{\frac{-3}{4}} 8^{\frac{2}{7}} \sqrt[6]{x^{5}} \sqrt[5]{y^{3}} \sqrt[7]{z}}{12^{12} 8^{12} 7^{2} x^{\frac{4}{5}} \sqrt[3]{y^{5}} z^{\frac{2}{6}}} * \frac{x^{\frac{-3}{4}} y^{\frac{2}{7}} z^{\frac{-8}{5}} s^{\frac{3}{2}}}{x^{2} y^{5} z^{\frac{2}{6}} s^{-9}}\right)^{\frac{7}{4}} \)
Algebra United Arab Emirates Jan 30, 2025
19. \( \frac{x^{-5} y^{4}}{y^{-3}} \)
Algebra United States Jan 30, 2025
B. \( x^{2}-3 x-28 \)
Algebra United Arab Emirates Jan 30, 2025
7. Efectueaza sis scrie rezultatul sub formă de putere: \( \begin{array}{lll}\text { a) } \frac{18}{5} \cdot\left(\frac{18}{5}\right)^{2}= & \text { b) }\left(\frac{6}{5}\right)^{2} \cdot\left(\frac{6}{5}\right)^{3} \cdot \frac{6}{5}= & \text { c) }\left(\frac{19}{5}\right)^{5} \cdot\left(\frac{19}{5}\right)^{16}= \\ \begin{array}{lll}\text { d) } \frac{3}{2} \cdot\left(\frac{3}{2}\right)^{3} \cdot\left(\frac{3}{2}\right)^{0} \cdot\left(\frac{3}{2}\right)^{4}= & \text { e) }\left[\left(\frac{28}{5}\right)^{2}\right]^{3}= & \text { f) }\left[\left(\frac{5}{6}\right)^{6}\right]^{7}= \\ \text { g) }\left[\left(\frac{24}{5}\right)^{2} \cdot\left(\frac{24}{5}\right)^{3}\right]^{8}= & \text { h) }\left[\frac{5}{7} \cdot\left(\frac{5}{7}\right)^{0} \cdot\left(\frac{5}{7}\right)^{4}\right]^{5}= & \text { i) }\left(\frac{29}{10}\right)^{10}:\left(\frac{29}{10}\right)^{7}=\end{array} \\ \left.\left.\begin{array}{lll}\text { j) }\left(\frac{1}{3}\right)^{17}: \frac{1}{3}= & \left.\text { k) }\left(\frac{3}{7}\right)^{11} \cdot\left(\frac{9}{49}\right)^{3}:\left(\frac{3}{7}\right)^{15}=1\right)\end{array}\right]\left(1 \frac{1}{2}\right)^{2}\right]^{8}:\left(\frac{3}{2}\right)^{13}= \\ \text { m) }\left(\frac{9}{10}\right)^{7} \cdot\left(\frac{1}{5}\right)^{7}= & \text { n) }\left(\frac{5}{2}\right)^{10} \cdot\left(\frac{8}{5}\right)^{10}: 2^{10}= & \text { o) } 9^{3} \cdot\left(\frac{7}{10}\right)^{3}:\left(\frac{63}{10}\right)^{3}= \\ \text { p) }\left[\left(\frac{1}{5}\right)^{7}\right]^{2} \cdot 6^{14}:\left(\frac{6}{5}\right)^{14}= & \text { q) }\left(\frac{5}{2}\right)^{7}:\left(\frac{5}{2}\right)^{5}= & \end{array} \)
Algebra Romania Jan 30, 2025

Latest Algebra Questions

7. Efectueaza sis scrie rezultatul sub formă de putere: \( \begin{array}{lll}\text { a) } \frac{18}{5} \cdot\left(\frac{18}{5}\right)^{2}= & \text { b) }\left(\frac{6}{5}\right)^{2} \cdot\left(\frac{6}{5}\right)^{3} \cdot \frac{6}{5}= & \text { c) }\left(\frac{19}{5}\right)^{5} \cdot\left(\frac{19}{5}\right)^{16}= \\ \begin{array}{lll}\text { d) } \frac{3}{2} \cdot\left(\frac{3}{2}\right)^{3} \cdot\left(\frac{3}{2}\right)^{0} \cdot\left(\frac{3}{2}\right)^{4}= & \text { e) }\left[\left(\frac{28}{5}\right)^{2}\right]^{3}= & \text { f) }\left[\left(\frac{5}{6}\right)^{6}\right]^{7}= \\ \text { g) }\left[\left(\frac{24}{5}\right)^{2} \cdot\left(\frac{24}{5}\right)^{3}\right]^{8}= & \text { h) }\left[\frac{5}{7} \cdot\left(\frac{5}{7}\right)^{0} \cdot\left(\frac{5}{7}\right)^{4}\right]^{5}= & \text { i) }\left(\frac{29}{10}\right)^{10}:\left(\frac{29}{10}\right)^{7}=\end{array} \\ \left.\left.\begin{array}{lll}\text { j) }\left(\frac{1}{3}\right)^{17}: \frac{1}{3}= & \left.\text { k) }\left(\frac{3}{7}\right)^{11} \cdot\left(\frac{9}{49}\right)^{3}:\left(\frac{3}{7}\right)^{15}=1\right)\end{array}\right]\left(1 \frac{1}{2}\right)^{2}\right]^{8}:\left(\frac{3}{2}\right)^{13}= \\ \text { m) }\left(\frac{9}{10}\right)^{7} \cdot\left(\frac{1}{5}\right)^{7}= & \text { n) }\left(\frac{5}{2}\right)^{10} \cdot\left(\frac{8}{5}\right)^{10}: 2^{10}= & \text { o) } 9^{3} \cdot\left(\frac{7}{10}\right)^{3}:\left(\frac{63}{10}\right)^{3}= \\ \text { p) }\left[\left(\frac{1}{5}\right)^{7}\right]^{2} \cdot 6^{14}:\left(\frac{6}{5}\right)^{14}= & \text { q) }\left(\frac{5}{2}\right)^{7}:\left(\frac{5}{2}\right)^{5}= & \end{array} \)
Algebra Romania Jan 30, 2025
B. \( x^{2}-3 x-28 \)
Algebra United Arab Emirates Jan 30, 2025
A. \( 3 x^{2}-x-10 \)
Algebra United Arab Emirates Jan 30, 2025
A. \( 3 x^{2}-x-10 \)
Algebra United Arab Emirates Jan 30, 2025
lify: \( \left(\frac{1447^{\frac{-3}{4}} 8^{\frac{2}{7}} \sqrt[6]{x^{5}} \sqrt[5]{y^{3}} \sqrt[7]{z}}{12^{12} 8^{12} 7^{2} x^{\frac{4}{5}} \sqrt[3]{y^{5}} z^{\frac{2}{6}}} * \frac{x^{\frac{-3}{4}} y^{\frac{2}{7}} z^{\frac{-8}{5}} s^{\frac{3}{2}}}{x^{2} y^{5} z^{\frac{2}{6}} s^{-9}}\right)^{\frac{7}{4}} \)
Algebra United Arab Emirates Jan 30, 2025
Prev Next
Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy