Find the slope and \( y \)-intercept of the line. Graph the line. \[ 5 x+y=9 \]
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To find the slope and \( y \)-intercept of the line given by the equation \( 5x + y = 9 \), we first need to rearrange it into the slope-intercept form, \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Starting with: \[ 5x + y = 9 \] Subtract \( 5x \) from both sides: \[ y = -5x + 9 \] Now, we can see that the slope \( m \) is \(-5\) and the \( y \)-intercept \( b \) is \(9\). This means the line crosses the \( y \)-axis at the point \((0, 9)\). To graph the line, you can start by plotting the y-intercept at (0, 9). From there, use the slope to find another point. Since the slope is \(-5\), you can move down 5 units and to the right 1 unit, landing on the point (1, 4). Connect these points with a straight line, and you've successfully graphed the line! Have fun sketching!