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Solke simultaneous Find the value of \( m \) and \( n \) \( \log m+2 \log n=6 \) \( \log m-\log n=4 \)

Ask by Hobbs Salazar. in Gambia
Jan 28,2025

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Tutor-Verified Answer

Answer

\( m = 10000\sqrt[3]{100} \) and \( n = \sqrt[3]{100} \).

Solution

Solve the system of equations \( \log(m)+2\log(n)=6;\log(m)-\log(n)=4 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}\log_{10}{\left(m\right)}+2\log_{10}{\left(n\right)}=6\\\log_{10}{\left(m\right)}-\log_{10}{\left(n\right)}=4\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}m=\frac{10^{6}}{n^{2}}\\\log_{10}{\left(m\right)}-\log_{10}{\left(n\right)}=4\end{array}\right.\) - step2: Substitute the value of \(m:\) \(\log_{10}{\left(\frac{10^{6}}{n^{2}}\right)}-\log_{10}{\left(n\right)}=4\) - step3: Subtract the terms: \(\log_{10}{\left(\frac{10^{6}}{n^{3}}\right)}=4\) - step4: Convert the logarithm into exponential form: \(\frac{10^{6}}{n^{3}}=10^{4}\) - step5: Evaluate the power: \(\frac{10^{6}}{n^{3}}=10000\) - step6: Cross multiply: \(10^{6}=n^{3}\times 10000\) - step7: Simplify the equation: \(10^{6}=10000n^{3}\) - step8: Rewrite the expression: \(10000\times 100=10000n^{3}\) - step9: Evaluate: \(100=n^{3}\) - step10: Swap the sides: \(n^{3}=100\) - step11: Simplify the equation: \(\sqrt[3]{n^{3}}=\sqrt[3]{100}\) - step12: Calculate: \(n=\sqrt[3]{100}\) - step13: Substitute the value of \(n:\) \(m=\frac{10^{6}}{\left(\sqrt[3]{100}\right)^{2}}\) - step14: Simplify: \(m=10^{4}\sqrt[3]{100}\) - step15: Calculate: \(m=10000\sqrt[3]{100}\) - step16: Calculate: \(\left\{ \begin{array}{l}m=10000\sqrt[3]{100}\\n=\sqrt[3]{100}\end{array}\right.\) - step17: Check the solution: \(\left\{ \begin{array}{l}m=10000\sqrt[3]{100}\\n=\sqrt[3]{100}\end{array}\right.\) - step18: Rewrite: \(\left(m,n\right) = \left(10000\sqrt[3]{100},\sqrt[3]{100}\right)\) The solution to the system of equations is \( m = 10000\sqrt[3]{100} \) and \( n = \sqrt[3]{100} \).

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The Deep Dive

To solve the given simultaneous equations, we can use the properties of logarithms. From the first equation: \[ \log m + 2 \log n = 6 \] This can be rewritten using the property that \( k \log a = \log(a^k) \): \[ \log m + \log(n^2) = 6 \] This implies: \[ \log(m \cdot n^2) = 6 \] So, we have: \[ m \cdot n^2 = 10^6 \quad \text{(1)} \] From the second equation: \[ \log m - \log n = 4 \] Which can be expressed as: \[ \log\left(\frac{m}{n}\right) = 4 \] This gives us: \[ \frac{m}{n} = 10^4 \quad \text{(2)} \] Now we have two equations: 1. \( m \cdot n^2 = 10^6 \) 2. \( m = 10^4 n \) Substituting equation (2) into equation (1): \[ (10^4 n) \cdot n^2 = 10^6 \] This simplifies to: \[ 10^4 n^3 = 10^6 \] Dividing both sides by \( 10^4 \): \[ n^3 = 10^{6-4} = 10^2 \] Taking the cube root: \[ n = 10^{2/3} \] Now substituting \( n \) back into equation (2) to find \( m \): \[ m = 10^4 (10^{2/3}) = 10^{4 + 2/3} = 10^{12/3 + 2/3} = 10^{14/3} \] Thus, the values of \( m \) and \( n \) are: \[ m = 10^{14/3}, \quad n = 10^{2/3} \]

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