Solke simultaneous Find the value of \( m \) and \( n \) \( \log m+2 \log n=6 \) \( \log m-\log n=4 \)
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To solve the given simultaneous equations, we can use the properties of logarithms. From the first equation: \[ \log m + 2 \log n = 6 \] This can be rewritten using the property that \( k \log a = \log(a^k) \): \[ \log m + \log(n^2) = 6 \] This implies: \[ \log(m \cdot n^2) = 6 \] So, we have: \[ m \cdot n^2 = 10^6 \quad \text{(1)} \] From the second equation: \[ \log m - \log n = 4 \] Which can be expressed as: \[ \log\left(\frac{m}{n}\right) = 4 \] This gives us: \[ \frac{m}{n} = 10^4 \quad \text{(2)} \] Now we have two equations: 1. \( m \cdot n^2 = 10^6 \) 2. \( m = 10^4 n \) Substituting equation (2) into equation (1): \[ (10^4 n) \cdot n^2 = 10^6 \] This simplifies to: \[ 10^4 n^3 = 10^6 \] Dividing both sides by \( 10^4 \): \[ n^3 = 10^{6-4} = 10^2 \] Taking the cube root: \[ n = 10^{2/3} \] Now substituting \( n \) back into equation (2) to find \( m \): \[ m = 10^4 (10^{2/3}) = 10^{4 + 2/3} = 10^{12/3 + 2/3} = 10^{14/3} \] Thus, the values of \( m \) and \( n \) are: \[ m = 10^{14/3}, \quad n = 10^{2/3} \]