A cyclist going downhill is accelerating at $$ 1.2 \mathrm{~m} / \mathrm{s}^{2} $$. If the final velocity of the cyclist is $$ 16 \mathrm{~m} / \mathrm{s} $$ after 10 seconds, what is the cyclist's initial velocity? $$ 4 \mathrm{~m} / \mathrm{s} $$ $$ 12 \mathrm{~m} / \mathrm{s} $$ $$ 18 \mathrm{~m} / \mathrm{s} $$ $$ 20 \mathrm{~m} / \mathrm{s} $$ .

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Given the kinematic equation

$$
v = u + at
$$

we are given:
- $$ v = 16 \, \mathrm{m/s} $$
- $$ a = 1.2 \, \mathrm{m/s^2} $$
- $$ t = 10 \, \mathrm{s} $$

We need to find the initial velocity $$ u $$. Rearranging the equation gives

$$
u = v - at
$$

Substitute the values:

$$
u = 16 - (1.2 \times 10)
$$

Calculate:

$$
u = 16 - 12 = 4 \, \mathrm{m/s}
$$

Thus, the cyclist's initial velocity is $$ 4 \, \mathrm{m/s} $$.
The cyclist's initial velocity is $$ 4 \, \mathrm{m/s} $$.

A cyclist going downhill is accelerating at . If the final velocity of the cyclist is after 10 seconds, what is
the cyclist’s initial velocity?

.

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A cyclist going downhill is accelerating at . If the final velocity of the cyclist is after 10 seconds, what is the cyclist’s initial velocity? .