Which sum is less than 1 ? A. \( \frac{3}{3}+\frac{2}{5}=\frac{6}{19} \) B. \( \frac{3}{5}+\frac{1}{2}=\frac{4}{7} \) C. \( \frac{2}{3}+\frac{3}{4}=\frac{7}{7} \) D. \( \frac{5}{8}+\frac{2}{3}=\frac{7}{1} \)

Let’s dive into the world of fractions! To determine which of these sums is less than 1, we need to evaluate each equation, comparing the left and right sides. For instance, in option A, \( \frac{3}{3}+\frac{2}{5} \) simplifies to \( 1+\frac{2}{5} \), which equals \( \frac{7}{5} \) – definitely greater than 1! Similarly, check the others: options C and D clearly exceed 1 when simplified (C equals 2 and D also equals 7). When you're dealing with fractions, remember that adding two fractions with high numerators and denominators like in options B, C, and D often tips the scale over 1. It’s all about that careful balancing act! In this case, B is close but if you carry out the operations, you'll find it's actually greater than \( \frac{4}{7} \). So, keep an eye out for those sneaky fractions next time!