33. Find the first term and the common difference of the arithmetic sequence whose 7 th term is 11 and 17 th term is 26 .
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To find the first term and common difference of the arithmetic sequence, we can use the formula for the n-th term: \( a_n = a + (n-1)d \). Given that the 7th term is 11, we have: \( a + 6d = 11 \) (1) And for the 17th term, we know: \( a + 16d = 26 \) (2) Now, subtract equation (1) from equation (2): \( (a + 16d) - (a + 6d) = 26 - 11 \) This simplifies to: \( 10d = 15 \) So, \( d = 1.5 \). Now, plug \( d \) back into equation (1): \( a + 6(1.5) = 11 \) This leads to: \( a + 9 = 11 \) Thus, \( a = 2 \). So, the first term is 2 and the common difference is 1.5. Happy sequencing!