Graph all vertical and horizontal asymptotes of the rational function. $$ f(x)=\frac{-5}{-4 x+2} $$

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Find the vertical asymptotes of the function $$ f(x)=-\frac{5}{-4x+2} $$.
Function by following steps:
- step0: Find the vertical asymptotes:
  $$f\left(xight)=-\frac{5}{-4x+2}$$
- step1: Evaluate the limit:
  $$\lim _{xightarrow \frac{1}{2}}\left(-\frac{5}{-4x+2}ight)$$
- step2: Rewrite the fraction:
  $$\lim _{xightarrow \frac{1}{2}}\left(\frac{-5}{-4x+2}ight)$$
- step3: Evaluate the left-hand and the right-hand limits:
  $$\begin{align}&\lim _{xightarrow \frac{1}{2}^{-}}\left(\frac{-5}{-4x+2}ight)\&\lim _{xightarrow \frac{1}{2}^{+}}\left(\frac{-5}{-4x+2}ight)\end{align}$$
- step4: Evaluate the left-hand limit:
  $$\begin{align}&-\infty\&+\infty\end{align}$$
- step5: Limit does not exist:
  $$	extrm{The limit does not exist}$$
- step6: $$x=\frac{1}{2}$$ is a vertical asymptote$$:$$
  $$\begin{align}&x=\frac{1}{2}	extrm{ }	extrm{is a vertical asymptote}\end{align}$$
- step7: List all vertical asymptotes of the function:
  $$\begin{align}&x=\frac{1}{2}\end{align}$$
Find the horizontal asymptotes of the function $$ f(x)=-\frac{5}{-4x+2} $$.
Function by following steps:
- step0: Find the horizontal asymptotes:
  $$f\left(xight)=-\frac{5}{-4x+2}$$
- step1: Evaluate the limits $$\lim _{xightarrow +\infty}\left(f\left(xight)ight)$$ and $$\lim _{xightarrow -\infty}\left(f\left(xight)ight):$$
  $$\begin{align}&\lim _{xightarrow +\infty}\left(-\frac{5}{-4x+2}ight)\&\lim _{xightarrow -\infty}\left(-\frac{5}{-4x+2}ight)\end{align}$$
- step2: Calculate:
  $$\begin{align}&0\&0\end{align}$$
- step3: The finite values are horizontal asymptotes:
  $$\begin{align}&f\left(xight)=0\end{align}$$
The vertical asymptote of the rational function $$ f(x)=-\frac{5}{-4x+2} $$ is $$ x=\frac{1}{2} $$, and the horizontal asymptote is $$ f(x)=0 $$.
The vertical asymptote is $$ x=\frac{1}{2} $$ and the horizontal asymptote is $$ f(x)=0 $$.

Graph all vertical and horizontal asymptotes of the rational function.

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