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Graph all vertical and horizontal asymptotes of the rational function. \[ f(x)=\frac{-5}{-4 x+2} \]

Ask by Frank Li. in the United States
Nov 17,2024

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Answer

The vertical asymptote is \( x=\frac{1}{2} \) and the horizontal asymptote is \( f(x)=0 \).

Solution

Find the vertical asymptotes of the function \( f(x)=-\frac{5}{-4x+2} \). Function by following steps: - step0: Find the vertical asymptotes: \(f\left(x\right)=-\frac{5}{-4x+2}\) - step1: Evaluate the limit: \(\lim _{x\rightarrow \frac{1}{2}}\left(-\frac{5}{-4x+2}\right)\) - step2: Rewrite the fraction: \(\lim _{x\rightarrow \frac{1}{2}}\left(\frac{-5}{-4x+2}\right)\) - step3: Evaluate the left-hand and the right-hand limits: \(\begin{align}&\lim _{x\rightarrow \frac{1}{2}^{-}}\left(\frac{-5}{-4x+2}\right)\\&\lim _{x\rightarrow \frac{1}{2}^{+}}\left(\frac{-5}{-4x+2}\right)\end{align}\) - step4: Evaluate the left-hand limit: \(\begin{align}&-\infty\\&+\infty\end{align}\) - step5: Limit does not exist: \(\textrm{The limit does not exist}\) - step6: \(x=\frac{1}{2}\) is a vertical asymptote\(:\) \(\begin{align}&x=\frac{1}{2}\textrm{ }\textrm{is a vertical asymptote}\end{align}\) - step7: List all vertical asymptotes of the function: \(\begin{align}&x=\frac{1}{2}\end{align}\) Find the horizontal asymptotes of the function \( f(x)=-\frac{5}{-4x+2} \). Function by following steps: - step0: Find the horizontal asymptotes: \(f\left(x\right)=-\frac{5}{-4x+2}\) - step1: Evaluate the limits \(\lim _{x\rightarrow +\infty}\left(f\left(x\right)\right)\) and \(\lim _{x\rightarrow -\infty}\left(f\left(x\right)\right):\) \(\begin{align}&\lim _{x\rightarrow +\infty}\left(-\frac{5}{-4x+2}\right)\\&\lim _{x\rightarrow -\infty}\left(-\frac{5}{-4x+2}\right)\end{align}\) - step2: Calculate: \(\begin{align}&0\\&0\end{align}\) - step3: The finite values are horizontal asymptotes: \(\begin{align}&f\left(x\right)=0\end{align}\) The vertical asymptote of the rational function \( f(x)=-\frac{5}{-4x+2} \) is \( x=\frac{1}{2} \), and the horizontal asymptote is \( f(x)=0 \).

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To find the vertical and horizontal asymptotes of the function \( f(x) = \frac{-5}{-4x + 2} \), let's start with the vertical asymptote. Vertical asymptotes occur where the denominator is zero and the function is undefined. Setting the denominator equal to zero: \[ -4x + 2 = 0 \] Solving for \( x \), we get: \[ -4x = -2 \quad \Rightarrow \quad x = \frac{1}{2} \] So, there is a vertical asymptote at \( x = \frac{1}{2} \). Now, for the horizontal asymptote, we look at the degrees of the numerator and the denominator. The function is a rational function where the degree of the numerator (which is a constant, so degree 0) is less than the degree of the denominator (which is linear, hence degree 1). According to rational function behavior, when the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is \( y = 0 \). In summary: - Vertical Asymptote: \( x = \frac{1}{2} \) - Horizontal Asymptote: \( y = 0 \) To graph them, you'll draw a dashed line for the vertical asymptote at \( x = \frac{1}{2} \) and a dashed line for the horizontal asymptote along the x-axis at \( y = 0 \).

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