1 Express the confidence interval $$ (0.432,0.52) $$ in the form $$ \hat{p} \pm E $$.

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The confidence interval is given as $$ (0.432,0.52) $$.

1. Compute the midpoint $$\hat{p}$$:
   $$
   \hat{p} = \frac{0.432 + 0.52}{2} = \frac{0.952}{2} = 0.476.
   $$

2. Compute the half-width $$E$$:
   $$
   E = \frac{0.52 - 0.432}{2} = \frac{0.088}{2} = 0.044.
   $$

Thus, the interval in the form $$\hat{p} \pm E$$ is:
$$
0.476 \pm 0.044.
$$
The confidence interval $$ (0.432, 0.52) $$ can be expressed as $$ 0.476 \pm 0.044 $$.

1 Express the confidence interval in the form .

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