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Give exact answers. Express numbers in simplest form using integers, fractions, or radicals.

Ask by Howell Bolton. in the United States
Mar 25,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

  • Center:
  • Vertices: and
  • Foci: and
  • Asymptotes:
To graph the hyperbola, plot the center at , vertices at and , foci at and , and draw the asymptotes and . The hyperbola opens upwards and downwards from the vertices.

Solution

The given equation is
This is the standard form of a hyperbola centered at with a vertical transverse axis. Let’s identify the components step by step.

(a) Identify the center.

The center of the hyperbola is given by the point . From the equation, we can see that:
Thus, the center is .

(b) Identify the vertices.

For a hyperbola of the form
the vertices are located at . Here, , so . Therefore, the vertices are:

© Identify the foci.

The foci of the hyperbola are located at , where . We have:
  • so
Thus, the foci are:

(d) Write equations for the asymptotes.

The equations for the asymptotes of a hyperbola in this form are given by:
Substituting the values we have:
The equations for the asymptotes are:
This simplifies to:

(e) Graph the hyperbola.

To graph the hyperbola, we will plot the center, vertices, foci, and asymptotes. The hyperbola opens upwards and downwards, with the vertices at and .
Now, let’s summarize the results:
  • Center:
  • Vertices: and
  • Foci: and
  • Asymptotes:
Next, I will graph the hyperbola.
It seems there was an issue with graphing the asymptotes directly. However, I can provide the equations for the asymptotes in a clearer format:
The equations for the asymptotes are:
These can be simplified further:

Summary of Results:

  • Center:
  • Vertices: and
  • Foci: and
  • Asymptotes:

Graphing the Hyperbola:

To graph the hyperbola, you would plot the center at , the vertices at and , the foci at and , and draw the asymptotes. The hyperbola will open upwards and downwards from the vertices.
If you need a visual representation, please let me know, and I can assist further!

Answered by UpStudy AI and reviewed by a Professional Tutor

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Explain
Simplify this solution

Mind Expander

The equation you provided represents a hyperbola in standard form. Let’s break it down step by step.
(a) Identify the center.
The center of the hyperbola can be derived from the standard form equation. In this case, the center is located at the point , where and are the values offset in the and directions, respectively. For , we identify it as since the expressions for and are not shifted. Thus, the center is at:

(b) Identify the vertices.
To find the vertices, we note that the hyperbola opens vertically (as indicated by being first) and the asymptotic structure. The distance to the vertices along the -axis is given by , which is the square root of the denominator under . In this case, so . The vertices are therefore:

© Identify the foci.
For hyperbolas, the distance from the center to the foci along the transverse axis is defined by where . In this hyperbola, and means , hence .
Now, calculate :
Thus, the foci are located at and :

(d) Write equations for the asymptotes.
The equations for the asymptotes of a hyperbola defined by (for horizontally opening hyperbola) or
In our case:
  1. The center is .
  2. and .
Thus, the slopes :
The equations for the asymptotes are:

(e) Graph the hyperbola.
To graph the hyperbola, start by plotting the center at . Next, plot the vertices at and . Draw the foci at and . The asymptotes will be represented as dashed lines emanating from the center, rising and falling at angles determined by the slopes calculated earlier. Finally, sketch the two “arms” of the hyperbola opening upwards and downwards, curving closer to the asymptotes but never touching them.
Happy graphing! 🌟

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