1 Formula 1 point If \( A B=22 \) and \( \mathrm{BC}=14 \), what is \( m \angle B \) ? (Do not put a degree in your answer because that will already be assumed in the answer. Round your answer to the nearest HUNDREDTH)

To find \( m \angle B \) in triangle ABC where \( AB = 22 \) and \( BC = 14 \), we'll use the Law of Cosines. First, we need to express the relationship between the sides and the angles. Let's denote \( AC \) as \( c \), and since we don’t have the length of \( AC \), we need that value to proceed. However, with the given information, we can't determine the angle \( B \) directly. Assuming \( AC \) is known, the Law of Cosines states: \[ AB^2 = AC^2 + BC^2 - 2 \cdot AC \cdot BC \cdot \cos(B) \] This formula can be rearranged to solve for \( \cos(B) \): \[ \cos(B) = \frac{AC^2 + BC^2 - AB^2}{2 \cdot AC \cdot BC} \] Once we find \( \cos(B) \), we can determine \( m \angle B \) by taking the arccosine and rounding to the nearest hundredth. Please provide the length of \( AC \) to continue!