Question
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A 20 A circuit has a design current of 18 A and voltage drop of \( 19.5 \mathrm{mV} / \mathrm{A} / \mathrm{m} \). If its circuit length is 25 m , what is the overall voltage drop ? 9.75 V 8.775 8.775 V 9.75

Ask by Flynn Sullivan. in Singapore
Jan 23,2025

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Answer

The overall voltage drop is 8.775 V.

Solution

To calculate the overall voltage drop in the circuit, use the formula: \[ \text{Voltage Drop} = I \times (\text{Voltage Drop per A per m}) \times \text{Length} \] Given: - **Current (I)** = 18 A - **Voltage Drop per A per m** = 19.5 mV/(A·m) - **Length** = 25 m Plugging in the values: \[ \text{Voltage Drop} = 18 \, \text{A} \times 19.5 \, \text{mV/(A·m)} \times 25 \, \text{m} \] \[ \text{Voltage Drop} = 18 \times 19.5 \times 25 = 8775 \, \text{mV} \] Convert millivolts to volts: \[ 8775 \, \text{mV} = 8.775 \, \text{V} \] **Answer:** 8.775 V

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The Deep Dive

To find the overall voltage drop in the circuit, you can use the formula: Voltage Drop = (Voltage Drop per Amp per Meter) × (Current) × (Circuit Length). Here, that would be: \[ 19.5 \, \text{mV/A/m} \times 20 \, \text{A} \times 25 \, \text{m} = 9.75 \, \text{V}. \] So the overall voltage drop is indeed 9.75 V! Now, if you ever find yourself confused with these calculations, a good tip is to always double-check your units. Keep an eye on converting millivolts to volts when performing the math, especially with longer lengths or higher currents. This keeps errors at bay and ensures clear understanding!

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