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Find the period and phase shift (horizontal shift) of the function. Answer exactly. \( f(x)=3 \tan (2 x+8) \) Period: Phase shift:

Ask by Romero Tucker. in the United States
Feb 03,2025

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The period is \( \frac{\pi}{2} \) and the phase shift is 4 units to the left.

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The period of the function \( f(x) = 3 \tan(2x + 8) \) can be calculated using the formula for the tangent function's period, which is \( \frac{\pi}{|b|} \), where \( b \) is the coefficient of \( x \). In this case, \( b = 2 \). Thus, the period is \( \frac{\pi}{2} \). For the phase shift, we rearrange the equation inside the tangent function \( 2x + 8 = 0 \) to find where it equals zero, which yields \( x = -4 \). Since tangent functions shift to the left when \( b > 0 \), the phase shift is \( -4 \) units.

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