Question 6 For the series \( 27,-9,3,-1 \ldots \), find: (i) the first term and the common ratio (ii) the sum of the first 6 terms
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The first term of the series is \( a = 27 \), and the common ratio \( r \) is found by dividing the second term by the first term: \( r = -9/27 = -\frac{1}{3} \). So, we have the first term as 27 and the common ratio as -1/3. To find the sum of the first 6 terms of the geometric series, we use the formula \( S_n = a \frac{1 - r^n}{1 - r} \). Plugging in our values gives us \( S_6 = 27 \frac{1 - (-\frac{1}{3})^6}{1 - (-\frac{1}{3})} \). Calculating this, we find \( S_6 = 27 \frac{1 - \frac{1}{729}}{1 + \frac{1}{3}} = 27 \frac{728/729}{4/3} = 27 \cdot \frac{728}{729} \cdot \frac{3}{4} = 27 \cdot \frac{546}{729} \). Thus, \( S_6 = \frac{14742}{729} \), which simplifies to approximately \( 20.19 \) when computed fully.