Specifications call for drilling a hole \( 0.636 \pm 0.005 \) in. in diameter. Will a \( \frac{41}{64} \)-in. hole be within the required tolerance? Will a \( \frac{41}{64} \)-in. hole be within the required tolerance? Yes No

To determine if a \( \frac{41}{64} \)-in. hole falls within the tolerance of \( 0.636 \pm 0.005 \) in., we need to convert \( \frac{41}{64} \) to a decimal format. This equals approximately \( 0.640625 \) in. Now, the acceptable diameter range for the hole is between \( 0.631 \) in. and \( 0.641 \) in. Since \( 0.640625 \) in. is greater than \( 0.641 \) in., it does not meet the specifications. Therefore, no, it does not fall within the required tolerance. To convert fractions like \( \frac{41}{64} \) to decimals, simply divide the numerator by the denominator. This method can be handy not only in engineering specifications but in various real-life scenarios, like cooking or carpentry, where precision in measurements is crucial!