Which fraction is greater than \( 1 \frac{1}{9} \) ? A. \( \frac{13}{9} \) B. \( \frac{11}{6} \) C. \( \frac{13}{11} \) D. \( \frac{4}{3} \)

To determine which fraction is greater than \( 1 \frac{1}{9} \), we can first convert the mixed number into an improper fraction. \( 1 \frac{1}{9} = \frac{9 \cdot 1 + 1}{9} = \frac{10}{9} \). Now let's convert each option to an improper fraction and compare them to \( \frac{10}{9} \): A. \( \frac{13}{9} \) (Clearly greater than \( \frac{10}{9} \)) B. \( \frac{11}{6} = \frac{22}{12} \approx 1.833 \) (This is greater than \( \frac{10}{9} \approx 1.111\)) C. \( \frac{13}{11} \approx 1.182 \) (Also greater than \( \frac{10}{9} \)) D. \( \frac{4}{3} = \frac{12}{9} \) (And this is greater than \( \frac{10}{9} \)) So, the options that are greater than \( 1 \frac{1}{9} \) are A, B, C, and D. However, to select just one correct answer, we can conclude that the correct answer could be either A, B, C, or D.