The line that passes through \( (3,5) \) and is parallel to the line through \( (3,3) \) and \( (-3,-1) \)
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To find the equation of the line that passes through \( (3,5) \) and is parallel to the line through \( (3,3) \) and \( (-3,-1) \), we first need to determine the slope of the line formed by the points \( (3,3) \) and \( (-3,-1) \). The slope \( m \) is calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 - 3}{-3 - 3} = \frac{-4}{-6} = \frac{2}{3} \] Since parallel lines share the same slope, the slope of the line through \( (3,5) \) will also be \( \frac{2}{3} \). Using the point-slope form of the line equation, \( y - y_1 = m(x - x_1) \), we plug in our known point and slope: \[ y - 5 = \frac{2}{3}(x - 3) \] Simplifying this, we can establish the equation of the desired line: \[ y - 5 = \frac{2}{3}x - 2 \] \[ y = \frac{2}{3}x + 3 \] So, the equation of the line is \( y = \frac{2}{3}x + 3 \).