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How does the graph of \( f(x)=\sqrt[3]{x} \) change when \( f(x) \) is replaced by \( f(-0.7 x \) (1 point) The graph is reflected over the \( x \)-axis and compresses horizontally. The graph is reflected over the \( y \)-axis and stretches horizontally. The graph is reflected over the \( x \)-axis and compresses vertically. The graph is reflected over the \( y \)-axis and stretches vertically.

Ask by Wright Brooks. in the United States
Jan 23,2025

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Answer

The graph is reflected over the y-axis and stretches horizontally.

Solution

The correct transformation is: **The graph is reflected over the \( y \)-axis and stretches horizontally.** **Explanation:** When replacing \( f(x) \) with \( f(-0.7x) \), the following transformations occur: 1. **Reflection over the \( y \)-axis:** The negative sign inside the function argument (\(-0.7x\)) causes the graph to flip horizontally. 2. **Horizontal Stretch:** The factor \( 0.7 \) (which is less than 1) causes the graph to stretch horizontally by a factor of \( \frac{1}{0.7} \). **Answer:** The graph is reflected over the y‑axis and stretches horizontally.

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Bonus Knowledge

When you replace \( f(x) = \sqrt[3]{x} \) with \( f(-0.7x) \), the graph undergoes two main transformations. First, the negative sign reflects the graph over the \( y \)-axis, meaning that positive values become negative and vice versa. Then the multiplication by \( 0.7 \) compresses the graph horizontally, making it narrow since the factor is less than one. Visualizing these transformations can be fun! Picture the original \( \sqrt[3]{x} \) graph like a friendly roller coaster that swings up to the right and down to the left. With the transformations applied, it flips into a mirror image over the \( y \)-axis while taking a compact, faster ride, thus creating a more pointed and steep appearance as it approaches the \( y \)-axis.

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