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6. Sketch the graph of: a) \( f(x)=\frac{x^{2}+x-6}{x^{3}-4 x^{2}-7 x+10} \quad \) b) \( f(x)=\frac{3 x^{2}-2 x+1}{x-1} \) c) \( f(x)=\frac{3 x^{2}+2}{x^{2}+4 x-5} \)

Ask by Alexander Brooks. in Ethiopia
Jan 18,2025

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Answer

To sketch the graphs of the given functions, identify vertical and horizontal asymptotes, find x-intercepts and y-intercepts, and plot key features accordingly.

Solution

It seems that the system does not currently support plotting graphs directly. However, I can guide you through the process of sketching the graphs of the given functions step by step. ### a) \( f(x) = \frac{x^{2}+x-6}{x^{3}-4x^{2}-7x+10} \) 1. **Factor the numerator and denominator:** - Numerator: \( x^2 + x - 6 = (x - 2)(x + 3) \) - Denominator: To factor \( x^3 - 4x^2 - 7x + 10 \), we can use synthetic division or trial and error to find roots. After testing, we find that \( x = 2 \) is a root. Dividing gives: \[ x^3 - 4x^2 - 7x + 10 = (x - 2)(x^2 - 2x - 5) \] - The quadratic \( x^2 - 2x - 5 \) can be solved using the quadratic formula: \[ x = \frac{2 \pm \sqrt{4 + 20}}{2} = 1 \pm \sqrt{6} \] 2. **Identify vertical asymptotes:** - Set the denominator equal to zero: \( (x - 2)(x^2 - 2x - 5) = 0 \) - Roots are \( x = 2, 1 + \sqrt{6}, 1 - \sqrt{6} \). 3. **Identify horizontal asymptotes:** - As \( x \to \infty \), the leading term of the numerator and denominator dominate: \[ f(x) \to 0 \quad \text{(horizontal asymptote at } y = 0\text{)} \] 4. **Find intercepts:** - **x-intercepts:** Set the numerator to zero: \( x^2 + x - 6 = 0 \) gives \( x = 2, -3 \). - **y-intercept:** Set \( x = 0 \): \( f(0) = \frac{-6}{10} = -0.6 \). ### b) \( f(x) = \frac{3x^{2}-2x+1}{x-1} \) 1. **Identify vertical asymptotes:** - Set the denominator equal to zero: \( x - 1 = 0 \) gives \( x = 1 \). 2. **Identify horizontal asymptotes:** - As \( x \to \infty \), the leading term of the numerator and denominator dominate: \[ f(x) \to 3x \quad \text{(no horizontal asymptote)} \] 3. **Find intercepts:** - **x-intercepts:** Set the numerator to zero: \( 3x^2 - 2x + 1 = 0 \) has no real roots (discriminant \( < 0 \)). - **y-intercept:** Set \( x = 0 \): \( f(0) = \frac{1}{-1} = -1 \). ### c) \( f(x) = \frac{3x^{2}+2}{x^{2}+4x-5} \) 1. **Factor the denominator:** - \( x^2 + 4x - 5 = (x + 5)(x - 1) \) 2. **Identify vertical asymptotes:** - Set the denominator equal to zero: \( (x + 5)(x - 1) = 0 \) gives \( x = -5, 1 \). 3. **Identify horizontal asymptotes:** - As \( x \to \infty \), the leading term of the numerator and denominator dominate: \[ f(x) \to 3 \quad \text{(horizontal asymptote at } y = 3\text{)} \] 4. **Find intercepts:** - **x-intercepts:** Set the numerator to zero: \( 3x^2 + 2 = 0 \) has no real roots. - **y-intercept:** Set \( x = 0 \): \( f(0) = \frac{2}{-5} = -0.4 \). ### Summary of Key Features - **Function a:** Vertical asymptotes at \( x = 2, 1 + \sqrt{6}, 1 - \sqrt{6} \); horizontal asymptote at \( y = 0 \); x-intercepts at \( x = 2, -3 \); y-intercept at \( -0.6 \). - **Function b:** Vertical asymptote at \( x = 1 \); no horizontal asymptote; y-intercept at \( -1 \). - **Function c:** Vertical asymptotes at \( x = -5, 1 \); horizontal asymptote at \( y = 3 \); y-intercept at \( -0.4 \). You can use this information to sketch the graphs of the functions. If you need further assistance or specific details, feel free to ask!

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Extra Insights

To visualize the graphs of these functions, let's dive into their unique characteristics and behaviors. The first function \( f(x) = \frac{x^{2}+x-6}{x^{3}-4x^{2}-7x+10} \) can be factored for further insight. The numerator factors into \( (x-2)(x+3) \) and the cubic denominator has roots that can be found using synthetic division or the Rational Root Theorem. Identifying these critical points will help in sketching its asymptotic behavior and intercepts. Next, consider \( f(x) = \frac{3x^{2}-2x+1}{x-1} \). This is a rational function where the denominator introduces a vertical asymptote at \( x = 1 \). For sketching, you'll notice that as \( x \) approaches 1 from either side, the function tends toward \( \pm \infty \), which creates an exciting point for viewers! Finally, for \( f(x) = \frac{3x^{2}+2}{x^{2}+4x-5} \), you can simplify areas where the denominator is zero to find vertical asymptotes. The numerator doesn't approach zero for real values, adding to the uniqueness of the graph's behavior as it will be bounded but diverges around the asymptotes found. Try plotting these functions with a graphing tool or software to see the fascinating shapes they create!

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