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Simplify by using order of operations: \[ \frac{10}{2+3}+\frac{6+3}{3} \]

Ask by Clark Boyd. in the United States
Jan 24,2025

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\[ 5 \]

Solution

To simplify the expression \(\frac{10}{2+3} + \frac{6+3}{3}\), follow the order of operations (PEMDAS/BODMAS): 1. **Parentheses/Brackets**: - Calculate inside the first denominator: \(2 + 3 = 5\) - Calculate inside the second numerator: \(6 + 3 = 9\) The expression now becomes: \[ \frac{10}{5} + \frac{9}{3} \] 2. **Division**: - \( \frac{10}{5} = 2 \) - \( \frac{9}{3} = 3 \) 3. **Addition**: - \( 2 + 3 = 5 \) **Final Answer:** \[ 5 \]

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To simplify the expression \(\frac{10}{2+3}+\frac{6+3}{3}\), we start with the operations in the parentheses: 1. For the first part: \(2 + 3 = 5\) So, \(\frac{10}{2+3} = \frac{10}{5} = 2\). 2. For the second part: \(6 + 3 = 9\) So, \(\frac{6+3}{3} = \frac{9}{3} = 3\). Now we combine the results: \[2 + 3 = 5\] Therefore, the simplified expression is \(5\).

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