$$ \left\{\begin{array}{l}3 x+3 y=0 \ 4 x=-4 y\end{array}\right. $$ 2: Determine if the point $$ (-3,3) $$ lies on both of the lines in the system of equations by substituting the ordered pair into both equations.

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To determine whether the point $$(-3, 3)$$ lies on both lines in the given system of equations, we'll substitute $$x = -3$$ and $$y = 3$$ into each equation and verify if the equations are satisfied.

The system of equations is:

$$
\begin{cases}
3x + 3y = 0 \quad &\text{(Equation 1)} \
4x = -4y \quad &\text{(Equation 2)}
\end{cases}
$$

### **Checking Equation 1: $$3x + 3y = 0$$**

Substitute $$x = -3$$ and $$y = 3$$:

$$
3(-3) + 3(3) = -9 + 9 = 0
$$

**Result:** The left-hand side equals the right-hand side ($$0 = 0$$), so the point $$(-3, 3)$$ satisfies **Equation 1**.

### **Checking Equation 2: $$4x = -4y$$**

Substitute $$x = -3$$ and $$y = 3$$:

$$
4(-3) = -4(3) \
-12 = -12
$$

**Result:** Both sides of the equation are equal ($$-12 = -12$$), so the point $$(-3, 3)$$ satisfies **Equation 2**.

### **Conclusion**

Since the point $$(-3, 3)$$ satisfies both equations in the system, it lies on both lines.

$$
\boxed{\text{Yes, the point } (-3,\ 3) \text{ lies on both lines.}}
$$
The point $$(-3, 3)$$ lies on both lines in the system of equations. $$ \boxed{\text{Yes, the point } (-3,\ 3) \text{ lies on both lines.}} $$

\[ \left\{\begin{array}{l}3 x+3 y=0 \\ 4 x=-4 y\end{array}\right. \] 2: Determine if the point \( (-3,3) \) lies on both of the lines in the system of equations by substituting the ordered pair into both equations.

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