Solve by using quadratic formula: \[ 2 x^{2}-5 x-3=0 \]
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To solve the quadratic equation \( 2x^2 - 5x - 3 = 0 \) using the quadratic formula, we first identify the coefficients \( a = 2 \), \( b = -5 \), and \( c = -3 \). The quadratic formula is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Plugging in the values: 1. **Calculate the discriminant (\( b^2 - 4ac \)):** - \( b^2 = (-5)^2 = 25 \) - \( 4ac = 4 \cdot 2 \cdot (-3) = -24 \) - Hence, \( b^2 - 4ac = 25 - (-24) = 25 + 24 = 49 \). 2. **Substituting in the quadratic formula:** - \( x = \frac{-(-5) \pm \sqrt{49}}{2 \cdot 2} \) - This simplifies to \( x = \frac{5 \pm 7}{4} \). 3. **Finding the two solutions:** - For \( 5 + 7 \): \( x = \frac{12}{4} = 3 \). - For \( 5 - 7 \): \( x = \frac{-2}{4} = -\frac{1}{2} \). So, the solutions are \( x = 3 \) and \( x = -\frac{1}{2} \).