Find the equation of the line through the point \( (2,-9) \) that is parallel to the line with equation \( y=\frac{11}{3} x-5 \). The equation is (Be sure to enter your answer as an equation)

To find the equation of the line that is parallel to \( y = \frac{11}{3} x - 5 \) and passes through the point \( (2, -9) \), we first note that parallel lines have the same slope. The slope from the given line is \( \frac{11}{3} \). Using the point-slope form of the equation of a line, which is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is the point, we substitute the slope and the point into the formula: \[ y - (-9) = \frac{11}{3}(x - 2) \] This simplifies to: \[ y + 9 = \frac{11}{3}(x - 2) \] Now we can distribute \( \frac{11}{3} \): \[ y + 9 = \frac{11}{3}x - \frac{22}{3} \] Next, we isolate \( y \) by subtracting \( 9 \) (or \( \frac{27}{3} \)) from both sides: \[ y = \frac{11}{3}x - \frac{22}{3} - \frac{27}{3} \] Combining the constants gives: \[ y = \frac{11}{3}x - \frac{49}{3} \] Thus, the equation of the line is: \[ y = \frac{11}{3}x - \frac{49}{3} \]