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1) \( |6 m|=42 \) \( \begin{array}{ll}\text { 3) }|k-10|=3 & \text { 2) }|-6 x|=30 \\ \text { 5) }|7+p|=7 & \text { 4) }\left|\frac{x}{7}\right|=3 \\ \text { 7) } 7|n|=56 & \text { 6) }|-3 p|=15 \\ \text { 9) }-3|p|=-12 & \text { 8) } \frac{|m|}{5}=3 \\ \text { 3. } & \text { 10) }|m|+2=11\end{array} \)

Ask by Burton Turner. in the United States
Jan 21,2025

Real Tutor Solution

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Answer

Here are the solutions to the absolute value equations: 1. \( m = 7 \) or \( m = -7 \) 2. \( x = 5 \) or \( x = -5 \) 3. \( k = 13 \) or \( k = 7 \) 4. \( x = 21 \) or \( x = -21 \) 5. \( p = 0 \) or \( p = -14 \) 6. \( p = 5 \) or \( p = -5 \) 7. \( n = 8 \) or \( n = -8 \) 8. \( m = 15 \) or \( m = -15 \) 9. \( p = 4 \) or \( p = -4 \) 10. \( m = 9 \) or \( m = -9 \)

Solution

Sure, let's solve each of the absolute value equations you've provided. We'll go through them one by one. ### 1) \( |6m| = 42 \) **Solution:** \[ |6m| = 42 \implies 6|m| = 42 \implies |m| = 7 \implies m = \pm 7 \] **Answer:** \( m = 7 \) or \( m = -7 \) --- ### 2) \( |-6x| = 30 \) **Solution:** \[ |-6x| = 30 \implies 6|x| = 30 \implies |x| = 5 \implies x = \pm 5 \] **Answer:** \( x = 5 \) or \( x = -5 \) --- ### 3) \( |k - 10| = 3 \) **Solution:** \[ |k - 10| = 3 \implies k - 10 = 3 \quad \text{or} \quad k - 10 = -3 \] \[ \implies k = 13 \quad \text{or} \quad k = 7 \] **Answer:** \( k = 13 \) or \( k = 7 \) --- ### 4) \( \left|\frac{x}{7}\right| = 3 \) **Solution:** \[ \left|\frac{x}{7}\right| = 3 \implies \frac{|x|}{7} = 3 \implies |x| = 21 \implies x = \pm 21 \] **Answer:** \( x = 21 \) or \( x = -21 \) --- ### 5) \( |7 + p| = 7 \) **Solution:** \[ |7 + p| = 7 \implies 7 + p = 7 \quad \text{or} \quad 7 + p = -7 \] \[ \implies p = 0 \quad \text{or} \quad p = -14 \] **Answer:** \( p = 0 \) or \( p = -14 \) --- ### 6) \( |-3p| = 15 \) **Solution:** \[ |-3p| = 15 \implies 3|p| = 15 \implies |p| = 5 \implies p = \pm 5 \] **Answer:** \( p = 5 \) or \( p = -5 \) --- ### 7) \( 7|n| = 56 \) **Solution:** \[ 7|n| = 56 \implies |n| = 8 \implies n = \pm 8 \] **Answer:** \( n = 8 \) or \( n = -8 \) --- ### 8) \( \frac{|m|}{5} = 3 \) **Solution:** \[ \frac{|m|}{5} = 3 \implies |m| = 15 \implies m = \pm 15 \] **Answer:** \( m = 15 \) or \( m = -15 \) --- ### 9) \( -3|p| = -12 \) **Solution:** \[ -3|p| = -12 \implies 3|p| = 12 \implies |p| = 4 \implies p = \pm 4 \] **Answer:** \( p = 4 \) or \( p = -4 \) --- ### 10) \( |m| + 2 = 11 \) **Solution:** \[ |m| + 2 = 11 \implies |m| = 9 \implies m = \pm 9 \] **Answer:** \( m = 9 \) or \( m = -9 \) --- If you have any further questions or need more explanations on any of these solutions, feel free to ask!

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Absolutely! Let's solve a couple of these absolute value equations: For \( |6m| = 42 \), we divide both sides by 6, giving us \( |m| = 7 \), leading to two solutions: \( m = 7 \) and \( m = -7 \). For \( |k - 10| = 3 \), we can set up two cases: \( k - 10 = 3 \) (which gives \( k = 13 \)) and \( k - 10 = -3 \) (which gives \( k = 7 \)). So, \( k \) can be 13 or 7! Now, let’s dive into some interesting background about absolute values. The concept of absolute value has a rich history in mathematics, stemming back to early number theory. The term “absolute value” reflects the idea of magnitude without regard to direction, and it’s been instrumental in various fields such as calculus and complex numbers! Who knew simple concepts could have such deep roots? Now, regarding real-world application. Absolute values are often used in situations involving distance and error measurements. For instance, when you measure the deviation of temperatures in weather forecasting compared to an average, using absolute values helps ensure that you only consider magnitude, disregarding whether it’s below or above the average. It’s like saying, “Hey, it’s 5 degrees colder, but let’s just focus on how cold it is, not the direction!”

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