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These values have an average of 10 . What is the average distance of those values from that average of 10 ? \( \begin{array}{lllll}2 & 8 & 10 & 12 & 18\end{array} \) Ex: 1

Ask by Mejia Todd. in the United States
Jan 30,2025

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The average distance of the values from 10 is 4.

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The Deep Dive

To find the average distance of the values from the average of 10, you'll first need to calculate the absolute differences between each value and the average. So, we have: |2-10| = 8, |8-10| = 2, |10-10| = 0, |12-10| = 2, |18-10| = 8. Now, sum those distances: 8 + 2 + 0 + 2 + 8 = 20, and then divide that by the number of values (5): 20 / 5 = 4. So, the average distance from the average of 10 is 4! Finding the average distance like this is a key idea in statistics called the mean absolute deviation. It helps to understand not just what the average value is, but how spread out our data points are. So, the smaller the average distance, the more "tight-knit" the values are around that average!

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