Question
upstudy study bank question image url

Classwork (Simplify \[ \frac{1}{x-4}+\frac{2}{x+3}-\frac{2}{x^{2}-x-12} \] \[ 2 \frac{x}{x+2}-\frac{2}{x-1}-\frac{6}{x^{2}+x-2} \]

Ask by Ford Patel. in South Africa
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

Simplify the expressions: 1. \( \frac{1}{x-4}+\frac{2}{x+3}-\frac{2}{x^{2}-x-12} \) simplifies to \( \frac{3x-7}{x^{2}-x-12} \). 2. \( 2 \frac{x}{x+2}-\frac{2}{x-1}-\frac{6}{x^{2}+x-2} \) simplifies to \( \frac{2x^{2}-4x-10}{x^{2}+x-2} \).

Solution

Calculate or simplify the expression \( \frac{1}{x-4}+\frac{2}{x+3}-\frac{2}{x^{2}-x-12} \). Simplify the expression by following steps: - step0: Solution: \(\frac{1}{x-4}+\frac{2}{x+3}-\frac{2}{x^{2}-x-12}\) - step1: Factor the expression: \(\frac{1}{x-4}+\frac{2}{x+3}-\frac{2}{\left(x-4\right)\left(x+3\right)}\) - step2: Reduce fractions to a common denominator: \(\frac{x+3}{\left(x-4\right)\left(x+3\right)}+\frac{2\left(x-4\right)}{\left(x+3\right)\left(x-4\right)}-\frac{2}{\left(x-4\right)\left(x+3\right)}\) - step3: Rewrite the expression: \(\frac{x+3}{\left(x-4\right)\left(x+3\right)}+\frac{2\left(x-4\right)}{\left(x-4\right)\left(x+3\right)}-\frac{2}{\left(x-4\right)\left(x+3\right)}\) - step4: Transform the expression: \(\frac{x+3+2\left(x-4\right)-2}{\left(x-4\right)\left(x+3\right)}\) - step5: Multiply the terms: \(\frac{x+3+2x-8-2}{\left(x-4\right)\left(x+3\right)}\) - step6: Calculate: \(\frac{3x-7}{\left(x-4\right)\left(x+3\right)}\) - step7: Multiply the terms: \(\frac{3x-7}{x^{2}-x-12}\) Calculate or simplify the expression \( 2 \frac{x}{x+2}-\frac{2}{x-1}-\frac{6}{x^{2}+x-2} \). Simplify the expression by following steps: - step0: Solution: \(\left(2\times \frac{x}{x+2}\right)-\frac{2}{x-1}-\frac{6}{x^{2}+x-2}\) - step1: Multiply the terms: \(\frac{2x}{x+2}-\frac{2}{x-1}-\frac{6}{x^{2}+x-2}\) - step2: Factor the expression: \(\frac{2x}{x+2}-\frac{2}{x-1}-\frac{6}{\left(x+2\right)\left(x-1\right)}\) - step3: Reduce fractions to a common denominator: \(\frac{2x\left(x-1\right)}{\left(x+2\right)\left(x-1\right)}-\frac{2\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}-\frac{6}{\left(x+2\right)\left(x-1\right)}\) - step4: Rewrite the expression: \(\frac{2x\left(x-1\right)}{\left(x+2\right)\left(x-1\right)}-\frac{2\left(x+2\right)}{\left(x+2\right)\left(x-1\right)}-\frac{6}{\left(x+2\right)\left(x-1\right)}\) - step5: Transform the expression: \(\frac{2x\left(x-1\right)-2\left(x+2\right)-6}{\left(x+2\right)\left(x-1\right)}\) - step6: Multiply the terms: \(\frac{2x^{2}-2x-2\left(x+2\right)-6}{\left(x+2\right)\left(x-1\right)}\) - step7: Multiply the terms: \(\frac{2x^{2}-2x-\left(2x+4\right)-6}{\left(x+2\right)\left(x-1\right)}\) - step8: Subtract the terms: \(\frac{2x^{2}-4x-10}{\left(x+2\right)\left(x-1\right)}\) - step9: Multiply the terms: \(\frac{2x^{2}-4x-10}{x^{2}+x-2}\) The simplified form of the first expression is \(\frac{3x-7}{x^{2}-x-12}\) and the simplified form of the second expression is \(\frac{2x^{2}-4x-10}{x^{2}+x-2}\).

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

The Deep Dive

To simplify the expression, start by factoring the denominators: The first denominator, \(x^2 - x - 12\), can be factored to \((x - 4)(x + 3)\). The second denominator, \(x^2 + x - 2\), factors to \((x - 1)(x + 2)\). Using these factorizations, rewrite the expression: \[ \frac{1}{x-4} + \frac{2}{x+3} - \frac{2}{(x-4)(x+3)} + 2 \frac{x}{x+2} - \frac{2}{x-1} - \frac{6}{(x-1)(x+2)} \] Next, find a common denominator, which would be the product of all distinct linear factors: \((x-4)(x+3)(x-1)(x+2)\). Combine the fractions by ensuring each has this common denominator, and simplify the numerators accordingly. This leads to a combined expression you can simplify further and solve for specific \(x\) values if desired. Remember to check for restrictions where \(x\) would make any denominator equal to zero! ----- Understanding rational expressions isn’t just about math on paper; it's crucial in fields like engineering and physics! For example, engineers might work with forces acting on varying structures where such expressions help in calculating loads. Recognizing how terms react and combine gives insights into system behavior, making the math not just an abstract concept but a tool for real-world solutions! For anyone looking to dive deeper into this subject, consider studying algebraic fractions and their applications in calculus. A good resource would be "College Algebra" by Michael Sullivan. This textbook breaks down rational expressions, discusses their properties, and shows how they’re used in problem-solving, making advanced topics more approachable and fun!

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy