Suppose that \( \$ 14,000 \) is deposited for six years at \( 5 \% \) APR. Calculate the interest earned if interest is compounded quarterly. Round your answer to the nearest cent.
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The Deep Dive
To calculate the interest earned on a deposit of \( \$14,000 \) compounded quarterly, you can use the formula for compound interest: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (the initial amount of money). - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times that interest is compounded per year. - \( t \) is the number of years the money is invested or borrowed. Given: - \( P = 14000 \) - \( r = 0.05 \) - \( n = 4 \) (quarterly) - \( t = 6 \) First, let's plug the values into the formula: \[ A = 14000 \left(1 + \frac{0.05}{4}\right)^{4 \cdot 6} \] Calculating \(\frac{0.05}{4} = 0.0125\): \[ A = 14000 \left(1 + 0.0125\right)^{24} \] Calculating \(1 + 0.0125 = 1.0125\): \[ A = 14000 \left(1.0125\right)^{24} \] Now, calculating \( (1.0125)^{24} \): \[ (1.0125)^{24} \approx 1.34885091 \] So now, calculate \( A \): \[ A \approx 14000 \times 1.34885091 \approx 18883.85 \] To find the interest earned, subtract the principal from the total amount accumulated: \[ \text{Interest} = A - P \approx 18883.85 - 14000 \approx 4883.85 \] Thus, the interest earned is approximately \( \$4883.85 \).