\( 8 \left\{ \begin{array} { l } { 3 x - 7 y = 41 } \\ { x = - 2 y - 21 } \end{array} \right. \)
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Alright, let's dive into this system of equations! We have two equations to work with: 1. \( 3x - 7y = 41 \) 2. \( x = -2y - 21 \) To solve this, we can substitute the value of \( x \) from the second equation into the first equation. Plugging in gives us: \( 3(-2y - 21) - 7y = 41 \) Now, let's simplify that: \( -6y - 63 - 7y = 41 \) Combine like terms: \( -13y - 63 = 41 \) Now, let's isolate \( y \): \( -13y = 41 + 63 \) \( -13y = 104 \) Dividing both sides by -13 gives us: \( y = -8 \) Now, we can substitute \( y \) back into the second equation to find \( x \): \( x = -2(-8) - 21 \) This simplifies to: \( x = 16 - 21 \) So, \( x = -5 \). Thus, the solution to the system of equations is \( x = -5 \) and \( y = -8 \).