Question
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\( w ^ { 2 } + 6 w + \square \)

Ask by Byrd Carrillo. in the United States
Jan 29,2025

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Tutor-Verified Answer

Answer

The missing number to complete the square is 9.

Solution

To complete the square for the quadratic expression \( w^2 + 6w + \square \), follow these steps: 1. **Identify the Coefficient of \( w \):** The coefficient of \( w \) is **6**. 2. **Take Half of This Coefficient:** \[ \frac{6}{2} = 3 \] 3. **Square the Result from Step 2:** \[ 3^2 = 9 \] 4. **Insert This Value into the Expression:** \[ w^2 + 6w + 9 \] 5. **Write the Completed Square:** The expression \( w^2 + 6w + 9 \) can be written as: \[ (w + 3)^2 \] **Final Completed Expression:** \[ w^2 + 6w + \mathbf{9} = (w + 3)^2 \] So, the missing number to complete the square is **9**.

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Bonus Knowledge

The expression \( w^2 + 6w + \square \) hints at completing the square. To make it a perfect square trinomial, we need to find the value of the square. Half of the coefficient of \( w \) (which is 6) is 3, and squaring that gives us 9. Therefore, the expression becomes \( w^2 + 6w + 9 \), which can be factored into \( (w+3)^2 \). Now, if you're ever faced with such an expression, remember to always take half of the linear coefficient, square it, and add it to complete the square. A common mistake is to overlook the need for adding this term, which can lead to an incomplete or incorrect factorization.

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