\( \int ( \frac { 2 } { x ^ { 6 } } + 7 - \frac { 6 } { x ^ { 2 } } ) d x = \square \)

Calculate the integral \( \int ( \frac{2}{x^6} + 7 - \frac{6}{x^2}) dx \). Evaluate the integral by following steps: - step0: Evaluate using formulas and rules: \(\int \left(\frac{2}{x^{6}}+7-\frac{6}{x^{2}}\right) dx\) - step1: Use properties of integrals: \(\int \frac{2}{x^{6}} dx+\int 7 dx+\int -\frac{6}{x^{2}} dx\) - step2: Evaluate the integral: \(-\frac{2}{5x^{5}}+\int 7 dx+\int -\frac{6}{x^{2}} dx\) - step3: Evaluate the integral: \(-\frac{2}{5x^{5}}+7x+\int -\frac{6}{x^{2}} dx\) - step4: Evaluate the integral: \(-\frac{2}{5x^{5}}+7x+\frac{6}{x}\) - step5: Add the constant of integral C: \(-\frac{2}{5x^{5}}+7x+\frac{6}{x} + C, C \in \mathbb{R}\) The integral of \( \frac{2}{x^6} + 7 - \frac{6}{x^2} \) with respect to \( x \) is \( -\frac{2}{5x^{5}}+7x+\frac{6}{x} + C \), where \( C \) is an arbitrary constant.