Question
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Bereken die volgende in terme van (in terms of) \( \bigcirc \). \( -40+(-2 \nabla)+150+(-\nabla) \)

Ask by Fleming Schofield. in South Africa
Feb 03,2025

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Answer

\( 110 - 3\,\bigcirc \)

Solution

Om die uitdrukking \( -40 + (-2 \nabla) + 150 + (-\nabla) \) in terme van \( \bigcirc \) te vereenvoudig, neem ons aan dat \( \nabla \) omskep kan word na \( \bigcirc \). Bereken die som van die konstante terme en die terme met \( \nabla \): \[ -40 + 150 = 110 \] \[ -2 \nabla - \nabla = -3 \nabla \] As ons \( \nabla \) vervang deur \( \bigcirc \), kry ons: \[ -3 \nabla = -3 \bigcirc \] Slegs kombineer die twee resultate: \[ 110 - 3 \bigcirc \] **Antwoord:** \( 110 - 3\,\bigcirc \)

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Om te bereken wat \( -40 + (-2 \nabla) + 150 + (-\nabla) \) in terme van \( \bigcirc \) is, moet ons eers die waarde van \( \nabla \) in terme van \( \bigcirc \) definieer. Stel \( \nabla \) gelyk aan \( k \cdot \bigcirc \) waar \( k \) 'n konstante is. As ons \( \nabla = k \bigcirc \) neem, kry ons: \[ -40 + (-2k \bigcirc) + 150 + (-k \bigcirc) = 110 - 2k \bigcirc - k \bigcirc = 110 - 3k \bigcirc. \] So, die uiteindelike uitdrukking in terme van \( \bigcirc \) is \( 110 - 3k \bigcirc \).

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